| ⇦ |
| ⇨ |
A particle is executing SHM along a straight line. Its velocities at distances x₁ and x₂ from the mean position are V₁ and V₂ respectively. Its time period is
Options
(a) 2π√x₂²-x₁²/V₁²-V₂²
(b) 2π√V₁²+V₂²/x₂²+x₁²
(c) 2π√V₁²-V₂²/x₁²-x₂²
(d) 2π√x₁²-x₂²/V₁²-V₂²
Correct Answer:
2π√x₂²-x₁²/V₁²-V₂²
Explanation:
No explanation available. Be the first to write the explanation for this question by commenting below.
Related Questions: - The number of photo electrons emitted for light of a frequency v
- The name of ions knocked out from the hot surface is
- A particle having a mass of 10⁻² kg carries a charge of 5 x 10⁻⁸C
- A Si and a Ge diode has identical physical dimensions. The bandgap in Si is larger
- A spring has time period T. It is cut into n equal parts. The time period of each part
Topics: Oscillations
(58)
Subject: Physics
(2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
- The number of photo electrons emitted for light of a frequency v
- The name of ions knocked out from the hot surface is
- A particle having a mass of 10⁻² kg carries a charge of 5 x 10⁻⁸C
- A Si and a Ge diode has identical physical dimensions. The bandgap in Si is larger
- A spring has time period T. It is cut into n equal parts. The time period of each part
Topics: Oscillations (58)
Subject: Physics (2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
18000+ students are using NEETLab to improve their score. What about you?
Solve Previous Year MCQs, Mock Tests, Topicwise Practice Tests, Identify Weak Topics, Formula Flash cards and much more is available in NEETLab Android App to improve your NEET score.
Share this page with your friends

Leave a Reply