| ⇦ |
| ⇨ |
The acceleration due to gravity at a place is π² m/sec². Then the time period of a simple pendulum of length one metre is
Options
(a) 2/π sec
(b) 2π sec
(c) 2 sec
(d) π sec
Correct Answer:
2 sec
Explanation:
No explanation available. Be the first to write the explanation for this question by commenting below.
Related Questions: - When an object is placed 40cm from a diverging lens, its virtual image is formed 20 cm
- In a common emitter (CE) amplifier having a voltage gain G, the transistor
- For a given velocity, a projectile has the same range R for two angles of projection.
- A Gaussian surface in the cylinder of cross-section πa² and length L is immersed
- A rocket is fired upward from the earth surface such that it creates an acceleration
Topics: Oscillations
(58)
Subject: Physics
(2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
- When an object is placed 40cm from a diverging lens, its virtual image is formed 20 cm
- In a common emitter (CE) amplifier having a voltage gain G, the transistor
- For a given velocity, a projectile has the same range R for two angles of projection.
- A Gaussian surface in the cylinder of cross-section πa² and length L is immersed
- A rocket is fired upward from the earth surface such that it creates an acceleration
Topics: Oscillations (58)
Subject: Physics (2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
18000+ students are using NEETLab to improve their score. What about you?
Solve Previous Year MCQs, Mock Tests, Topicwise Practice Tests, Identify Weak Topics, Formula Flash cards and much more is available in NEETLab Android App to improve your NEET score.
Share this page with your friends

Leave a Reply