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The wavelength of first line of Balmer series is 6563Å. The wavelength of first line of Lyman series will be
Options
(a) 1215.4Å
(b) 2500Å
(c) 7500Å
(d) 600Å
Correct Answer:
1215.4Å
Explanation:
λ(ʟyman) / λ(вalmer) = [(1/2²) – (1/3²)] / [(1/1²) – (1/2)²] = 5 / 27
λ(ʟyman) = (5 / 27) × λ(вalmer) = (5 / 27) × 6563 = 1215.4 Å
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Topics: Atoms and Nuclei
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Subject: Physics
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Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
- An object moving with a speed of 6.25 m/s, is deaccelerated at a rate given by
- An electric dipole of length 1 cm is placed with the axis making an angle of 30⁰
- Magnetism of a magnet is due to
- Surface tension of a solution is 30 x 10⁻² N/m. The radius of the soap bubble is 5 cm
- Two metallic spheres of radii 1 cm and 3 cm are given charges of -1 x 10⁻² C
Topics: Atoms and Nuclei (136)
Subject: Physics (2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
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