| ⇦ | 
| ⇨ |
Two metallic spheres of radii 1 cm and 3 cm are given charges of -1 x 10⁻² C and 5 x 10⁻² C, respectively. If these are connected by a conducting wire, the final charge on the bigger sphere is:
Options
(a) 2 x 10⁻² C
(b) 3 x 10⁻² C
(c) 4 x 10⁻² C
(d) 1 x 10⁻² C
Correct Answer:
3 x 10⁻² C
Explanation:
At equilibrium potential of both sphere becomes same if charge of sphere one x where Q= 4 x 10 10⁻² C
v₁ = v₂ kx / 1cm = k(Q – x) / 3 cm
3x = Q – x 4x = Q
x = Q/4 = 4 x 10⁻² / 4 C = 1 x 10⁻²
Q’ = Q – x = 3 x 10⁻² C
Related Questions: - The focal length of the objective of a terrestrial telescope is 80 cm
- An iron rod of volume 10⁻⁴ m³ and relative permeability 1000 is placed inside a long
- Two waves of same amplitude superpose. The resultant intensity is I₁
- A horizontal straight conductor kept in north-south direction falls under gravity. Then
- A parallel plate air capacitor has capacity C, distance of seperation between plate
Topics: Electrostatics
(146)
Subject: Physics
(2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
- The focal length of the objective of a terrestrial telescope is 80 cm
- An iron rod of volume 10⁻⁴ m³ and relative permeability 1000 is placed inside a long
- Two waves of same amplitude superpose. The resultant intensity is I₁
- A horizontal straight conductor kept in north-south direction falls under gravity. Then
- A parallel plate air capacitor has capacity C, distance of seperation between plate
Topics: Electrostatics (146)
Subject: Physics (2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
18000+ students are using NEETLab to improve their score. What about you?
Solve Previous Year MCQs, Mock Tests, Topicwise Practice Tests, Identify Weak Topics, Formula Flash cards and much more is available in NEETLab Android App to improve your NEET score.
Share this page with your friends
Leave a Reply