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An object moving with a speed of 6.25 m/s, is deaccelerated at a rate given by (dv/dt)= -2.5√v, where v is the instantaneous speed.The time taken by the object ,to come to rest would be
Options
(a) 2 s
(b) 4 s
(c) 8 s
(d) 1 s
Correct Answer:
2 s
Explanation:
No explanation available. Be the first to write the explanation for this question by commenting below.
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Topics: Motion in Straight Line
(93)
Subject: Physics
(2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
- Equal charge q each are placed at the vertices AQ and B of an equilateral triangle
- There is a ring of radius r having linear charge densityλ and rotating with a uniform
- A gramophone record is revolving with an angular velocity ?. A coin is placed at
- A motor-cyclist drives a motor cycle in a vertical circle. His minimum velocity
- A spring gun of spring constant 90 N/cm is compressed 12 cm by a ball of mass
Topics: Motion in Straight Line (93)
Subject: Physics (2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
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