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An object moving with a speed of 6.25 m/s, is deaccelerated at a rate given by (dv/dt)= -2.5√v, where v is the instantaneous speed.The time taken by the object ,to come to rest would be
Options
(a) 2 s
(b) 4 s
(c) 8 s
(d) 1 s
Correct Answer:
2 s
Explanation:
No explanation available. Be the first to write the explanation for this question by commenting below.
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Topics: Motion in Straight Line
(93)
Subject: Physics
(2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
- A particle executing simple harmonic motion of amplitude 5 cm has maximum
- The Rutherford scattering experiment proves that an atom consists of
- A body of mass m is thrown upwards at an angle θ with the horizontal with velocity
- Two small spherical shells A and B are given positive charges of 9C and 4C
- A dip needle vibrates in a vertical plane perpendicular to magnetic meridian. The time
Topics: Motion in Straight Line (93)
Subject: Physics (2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
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