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An object moving with a speed of 6.25 m/s, is deaccelerated at a rate given by (dv/dt)= -2.5√v, where v is the instantaneous speed.The time taken by the object ,to come to rest would be
Options
(a) 2 s
(b) 4 s
(c) 8 s
(d) 1 s
Correct Answer:
2 s
Explanation:
No explanation available. Be the first to write the explanation for this question by commenting below.
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Topics: Motion in Straight Line
(93)
Subject: Physics
(2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
- The order of distance of an electron revolving in an atom from nucleus is
- If emf induced in a coil is 2 V by changing the current in it from 8 A to 6 A
- Two parallel metal plates having charges +Q and -Q face each other at a certain
- If a proton, a deuteron and an alpha particle, on being accelerated by the same
- The momentum of a photon of energy 1 MeV in kg m/s will be
Topics: Motion in Straight Line (93)
Subject: Physics (2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
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