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An object moving with a speed of 6.25 m/s, is deaccelerated at a rate given by (dv/dt)= -2.5√v, where v is the instantaneous speed.The time taken by the object ,to come to rest would be
Options
(a) 2 s
(b) 4 s
(c) 8 s
(d) 1 s
Correct Answer:
2 s
Explanation:
No explanation available. Be the first to write the explanation for this question by commenting below.
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Topics: Motion in Straight Line
(93)
Subject: Physics
(2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
- A beam of light of λ=600 nm from a distant source falls on a single slit 1 mm wide
- If in a L-R series circuit the power factor is 1/2 and R=100Ω, then the value of L is,
- Find out the e.m.f. produced when the current changes from 0 to 1 A in 10 sec.
- If sound wave travel from air to water, which of the following remains unchanged?
- A charged particle experiences magnetic force in the presence of magnetic field.
Topics: Motion in Straight Line (93)
Subject: Physics (2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
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