| ⇦ | 
| ⇨ |
An object moving with a speed of 6.25 m/s, is deaccelerated at a rate given by (dv/dt)= -2.5√v, where v is the instantaneous speed.The time taken by the object ,to come to rest would be
Options
(a) 2 s
(b) 4 s
(c) 8 s
(d) 1 s
Correct Answer:
2 s
Explanation:
No explanation available. Be the first to write the explanation for this question by commenting below.
Related Questions: - A planet moving along an elliptical orbit is closest to the sun at a distance of r₁
- In a franhofer diffraction experiment at a single slit using a light of wavelength
- A uniform rope of length 12 m and mass 6 kg hangs vertically from a rigid support.
- A certain current on passing through a galvanometer produces a deflection
- Three identical spherical shells, each of mass m and radius r are placed
Topics: Motion in Straight Line
(93)
Subject: Physics
(2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
- A planet moving along an elliptical orbit is closest to the sun at a distance of r₁
- In a franhofer diffraction experiment at a single slit using a light of wavelength
- A uniform rope of length 12 m and mass 6 kg hangs vertically from a rigid support.
- A certain current on passing through a galvanometer produces a deflection
- Three identical spherical shells, each of mass m and radius r are placed
Topics: Motion in Straight Line (93)
Subject: Physics (2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
18000+ students are using NEETLab to improve their score. What about you?
Solve Previous Year MCQs, Mock Tests, Topicwise Practice Tests, Identify Weak Topics, Formula Flash cards and much more is available in NEETLab Android App to improve your NEET score.
Share this page with your friends
Leave a Reply