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An object moving with a speed of 6.25 m/s, is deaccelerated at a rate given by (dv/dt)= -2.5√v, where v is the instantaneous speed.The time taken by the object ,to come to rest would be
Options
(a) 2 s
(b) 4 s
(c) 8 s
(d) 1 s
Correct Answer:
2 s
Explanation:
No explanation available. Be the first to write the explanation for this question by commenting below.
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Topics: Motion in Straight Line
(93)
Subject: Physics
(2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
- The ratio of magnetic dipole moment of an electron of charge e and mass m
- A particle is released from rest from a tower of height h, i.e,t₁ : t₂ : t₃ is
- A galvanometer of 50 Ω resistance has 25 divisions. A current of 4×10⁻⁴ A gives
- A long horizontal rod has a bead which can slide long its length
- Which of the following phenomenon exhibited the particle nature of light?
Topics: Motion in Straight Line (93)
Subject: Physics (2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
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