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An object moving with a speed of 6.25 m/s, is deaccelerated at a rate given by (dv/dt)= -2.5√v, where v is the instantaneous speed.The time taken by the object ,to come to rest would be
Options
(a) 2 s
(b) 4 s
(c) 8 s
(d) 1 s
Correct Answer:
2 s
Explanation:
No explanation available. Be the first to write the explanation for this question by commenting below.
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Topics: Motion in Straight Line
(93)
Subject: Physics
(2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
- A generator at a utility company produces 100 A of current at 4000 V. The voltage
- A uniform rope of length 12 m and mass 6 kg hangs vertically from a rigid support.
- A body is moving with velocity 30 m/s towards east. After 10 seconds its velocity
- To observed diffraction, the size of the obstacle
- The self-inductance of a choke coil is 10 mH. When it is connected with a 10 V DC source,
Topics: Motion in Straight Line (93)
Subject: Physics (2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
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