The ratio of longest wavelength corresponding to Lyman and Blamer series

The Ratio Of Longest Wavelength Corresponding To Lyman And Blamer Physics Question

The ratio of longest wavelength corresponding to Lyman and Blamer series in hydrogen spectrum is

Options

(a) 3 / 23
(b) 7 / 29
(c) 9 / 13
(d) 5 / 27

Correct Answer:

5 / 27

Explanation:

For Lyman series (2 → 1)
1/λL = R [1 – 1/2] = 3R/4
For Balmer series (3 → 2)
1/λB = R [1/4 – 1/9] = 5R/36
λL / λB = 4/3R / 36/5R = 4/36 (5/3) = 5/27

Related Questions:

  1. For a satellite moving in an orbit around the earth, the ratio of kinetic
  2. A body weighs 50 grams in air and 40 grams in water. How much would it weigh in a liquid
  3. Light of frequency 8×10¹⁵ Hz is incident on a substance of photoelectric work
  4. The output of OR gate is 1(one)
  5. The work function of sodium is 2.3 eV. The threshold wavelength of sodium will be

Topics: Atoms and Nuclei (136)
Subject: Physics (2479)

Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score

18000+ students are using NEETLab to improve their score. What about you?

Solve Previous Year MCQs, Mock Tests, Topicwise Practice Tests, Identify Weak Topics, Formula Flash cards and much more is available in NEETLab Android App to improve your NEET score.

NEETLab Mobile App

Share this page with your friends

Be the first to comment

Leave a Reply

Your email address will not be published.


*