| ⇦ | 
| ⇨ |
The ratio of longest wavelength corresponding to Lyman and Blamer series in hydrogen spectrum is
Options
(a) 3 / 23
(b) 7 / 29
(c) 9 / 13
(d) 5 / 27
Correct Answer:
5 / 27
Explanation:
For Lyman series (2 → 1)
1/λL = R [1 – 1/2] = 3R/4
For Balmer series (3 → 2)
1/λB = R [1/4 – 1/9] = 5R/36
λL / λB = 4/3R / 36/5R = 4/36 (5/3) = 5/27
Related Questions: - Suppose the kinetic energy of a body oscillating with amplitude A and at a distance
- A ship A is moving westwards with a speed of 10 km/h .The time after
- The magnetic susceptibility of a material of a rod is 299. Permeability of vacuum
- A thin wire of length L and mass M is bent to form a semicircle.
- When volume of a system is increased two times and temperature is decreased
Topics: Atoms and Nuclei
(136)
Subject: Physics
(2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
- Suppose the kinetic energy of a body oscillating with amplitude A and at a distance
- A ship A is moving westwards with a speed of 10 km/h .The time after
- The magnetic susceptibility of a material of a rod is 299. Permeability of vacuum
- A thin wire of length L and mass M is bent to form a semicircle.
- When volume of a system is increased two times and temperature is decreased
Topics: Atoms and Nuclei (136)
Subject: Physics (2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
18000+ students are using NEETLab to improve their score. What about you?
Solve Previous Year MCQs, Mock Tests, Topicwise Practice Tests, Identify Weak Topics, Formula Flash cards and much more is available in NEETLab Android App to improve your NEET score.
Share this page with your friends
Leave a Reply