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The wavelength of first line of Balmer series is 6563Å. The wavelength of first line of Lyman series will be
Options
(a) 1215.4Å
(b) 2500Å
(c) 7500Å
(d) 600Å
Correct Answer:
1215.4Å
Explanation:
λ(ʟyman) / λ(вalmer) = [(1/2²) – (1/3²)] / [(1/1²) – (1/2)²] = 5 / 27
λ(ʟyman) = (5 / 27) × λ(вalmer) = (5 / 27) × 6563 = 1215.4 Å
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Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
- A tangent galvanometer has a coil of 50 turns and a radius of 20 cm. The horizontal
- Planck’s constant has same dimensions as those of
- A neutron is moving with a velocity u.It collides head on and elastically with an atom
- Laser light is considered to be coherant because it consists of
- A particle of mass ‘m’ is kept at rest at a height 3R from the surface of earth
Topics: Atoms and Nuclei (136)
Subject: Physics (2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
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