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A simple pendulum performs simple harmonic motion about x = 0 with an amplitude a and time period T. The speed of the pendulum at x = a/2 will be:
Options
(a) πa / T
(b) 3π²a / T
(c) πa√3 / T
(d) πa√3 / 2T
Correct Answer:
πa√3 / T
Explanation:
Speed v = ? √(a² – x²) , x = a / 2
v = ? √(a² – a² / 4) = ? √(3a² / 4) = 2π / T . a√3 / 2
πa√3 / T
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Topics: Oscillations
(58)
Subject: Physics
(2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
- The equations of motion of a projectile are given by x=36 t metre and 2y=96t-9.8t²
- Angle of minimum deviation for a prism of reractive index 1.5 equal to the angle
- The instantaneous angular position of a point on a rotating wheel is given by
- A block of mass m moving at a velocity v collides with another block of mass 2m
- A cell can be balanced against 110 cm and 100 cm of potentiometer wire, respectively
Topics: Oscillations (58)
Subject: Physics (2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
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