The instantaneous angular position of a point on a rotating wheel is given by

The Instantaneous Angular Position Of A Point On A Rotating Physics Question

The instantaneous angular position of a point on a rotating wheel is given by the equation θ(t) = 2t³ – 6t². The torque on the wheel becomes zero at

Options

(a) t = 1 s
(b) t = 0.5 s
(c) t = 0.25 s
(d) t = 2 s

Correct Answer:

t = 1 s

Explanation:

When angular acceleration is zero then torque on the wheel becomes zero.
θ(t) = 2t – 6t
dθ / dt = 6t – 12t
= dθ / dt = 12t – 12 = 0
t = 1 s

Related Questions:

  1. The work function for aluminium is 4.125 eV. The cutoff wavelength for photoelectric
  2. The radius of orbit of a planet is two times that of the earth. The time period
  3. The conducting loop in the form of a circle is placed in a uniform magneitc field
  4. The control rods used in a nuclear reactor can be made up of
  5. α-particles, deuterons and protons of same energy are moving in a perpendicular

Topics: Motion of system of Particles and Rigid Body (73)
Subject: Physics (2479)

Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score

18000+ students are using NEETLab to improve their score. What about you?

Solve Previous Year MCQs, Mock Tests, Topicwise Practice Tests, Identify Weak Topics, Formula Flash cards and much more is available in NEETLab Android App to improve your NEET score.

NEETLab Mobile App

Share this page with your friends

Be the first to comment

Leave a Reply

Your email address will not be published.


*