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The instantaneous angular position of a point on a rotating wheel is given by the equation θ(t) = 2t³ – 6t². The torque on the wheel becomes zero at
Options
(a) t = 1 s
(b) t = 0.5 s
(c) t = 0.25 s
(d) t = 2 s
Correct Answer:
t = 1 s
Explanation:
When angular acceleration is zero then torque on the wheel becomes zero.
θ(t) = 2t – 6t
dθ / dt = 6t – 12t
= dθ / dt = 12t – 12 = 0
t = 1 s
Related Questions: - An object is placed 30 cm away from a convex lens of focal length 10 cm and a sharp
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Topics: Motion of system of Particles and Rigid Body
(73)
Subject: Physics
(2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
- An object is placed 30 cm away from a convex lens of focal length 10 cm and a sharp
- The temperature coefficient of the resistance of a wire is 0.00125 per ⁰C.
- If the earth shrink such that its mass does not change but radius decreases to one
- A particle is moving with a uniform velocity along a straight line path
- Heat produced in a resistance according to which law?
Topics: Motion of system of Particles and Rigid Body (73)
Subject: Physics (2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
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