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Two simple harmonic motions of angular frequency 100 and 1000 rad s⁻¹ have the same displacement amplitude. The ratio of other maximum accelerations is:
Options
(a) 1 : 10
(b) 1 : 10²
(c) 1 : 10³
(d) 1 : 10⁴
Correct Answer:
1 : 10²
Explanation:
Maximum acceleration of a particle in the simple harmonic motion is directly proportional to the square of angular frequency i.e., a(max)= – w ² A
As A remains same, we can say
a₁ / a₂ = w₁² / w₂² = (100)² / (1000)² = 1 / 100
⇒ a₁ : a₂ = 1 : 10²
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Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
- Two circuits have a mutual inductance of 0.1 H. What average e.m.f. is induced
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- The magnetic field due to a current carrying circular loop of radius 3 cm at a point
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- Two identical capacitors each of capacitance 5 mF are charged potentials 2 kV and 1 kV
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Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
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