| ⇦ |
| ⇨ |
Two simple harmonic motions of angular frequency 100 and 1000 rad s⁻¹ have the same displacement amplitude. The ratio of other maximum accelerations is:
Options
(a) 1 : 10
(b) 1 : 10²
(c) 1 : 10³
(d) 1 : 10⁴
Correct Answer:
1 : 10²
Explanation:
Maximum acceleration of a particle in the simple harmonic motion is directly proportional to the square of angular frequency i.e., a(max)= – w ² A
As A remains same, we can say
a₁ / a₂ = w₁² / w₂² = (100)² / (1000)² = 1 / 100
⇒ a₁ : a₂ = 1 : 10²
Related Questions: - The kinetic energy of an electron in the first excited state is
- A capacitor of capacitance 100μF is charged by connecting it to a battery of voltage
- A rod of 10 cm length is moving perpendicular to uniform magntic field of intensity
- The average power dissipated in AC circuit is 2 W. If a current flowing through
- A body of mass 2 kg travels according to the law x(t)=pt+qt²+rt³
Topics: Oscillations
(58)
Subject: Physics
(2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
- The kinetic energy of an electron in the first excited state is
- A capacitor of capacitance 100μF is charged by connecting it to a battery of voltage
- A rod of 10 cm length is moving perpendicular to uniform magntic field of intensity
- The average power dissipated in AC circuit is 2 W. If a current flowing through
- A body of mass 2 kg travels according to the law x(t)=pt+qt²+rt³
Topics: Oscillations (58)
Subject: Physics (2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
18000+ students are using NEETLab to improve their score. What about you?
Solve Previous Year MCQs, Mock Tests, Topicwise Practice Tests, Identify Weak Topics, Formula Flash cards and much more is available in NEETLab Android App to improve your NEET score.
Share this page with your friends

Leave a Reply