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Two simple harmonic motions of angular frequency 100 and 1000 rad s⁻¹ have the same displacement amplitude. The ratio of other maximum accelerations is:
Options
(a) 1 : 10
(b) 1 : 10²
(c) 1 : 10³
(d) 1 : 10⁴
Correct Answer:
1 : 10²
Explanation:
Maximum acceleration of a particle in the simple harmonic motion is directly proportional to the square of angular frequency i.e., a(max)= – w ² A
As A remains same, we can say
a₁ / a₂ = w₁² / w₂² = (100)² / (1000)² = 1 / 100
⇒ a₁ : a₂ = 1 : 10²
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Subject: Physics
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Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
- Two particles P and Q start from origin and execute simple harmonic motion along X-axis
- Alternating current is transmitted to distant places at
- When a mass m is attached to a spring, it normally extends by 0.2 m.
- If in a p-n junction, a square input signal of 10 V is applied as shown, then the output
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Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
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