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An alpha nucleus of energy 1/2 mv² bombards a heavy nuclear target of charge Ze. Then the distance of closest approach for the alpha nucleus will be proportional to
Options
(a) 1 / Ze
(b) v²
(c) 1 / m
(d) 1 / v⁴
Correct Answer:
1 / m
Explanation:
Kinetic energy of alpha nucleus is equal to electrostatic potential energy of the system of the alpha particle and the heavy nucleus. That is,
1/2 mv² = 1/4π?￢ﾂﾀ . qαZe / r₀
where r₀ is the distance of closest approach
r₀ = 2/4π?￢ﾂﾀ . qαZe / mv²
r₀ ∞ Ze ∞ qα ∞ 1/m ∞ 1/v²
Hence option (c) is correct.
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Topics: Atoms and Nuclei
(136)
Subject: Physics
(2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
- When the disc rotates with uniform angulr velocity.Which of the following is not true?
- A circular disc X of radius R is made from an iron plate of thickness t and another disc
- A spring balance is attached to the ceiling of a lift.A man hangs his bag on the spring
- If a solid ball of metal has a concentric spherical cavity with in it if the ball
- At a metro station, a girl walks up a stationary escalator in time t₁
Topics: Atoms and Nuclei (136)
Subject: Physics (2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
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