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The ratio of amplitude of magnetic field to the amplitude of electric field for an electromagnetic wave propagating in vacuum is equal to:
Options
(a) The speed of light in vacuum
(b) reciprocal of speed of light in vacuum
(c) the ratio of magnetic permeability to the electric susceptibility of vacuum
(d) unity
Correct Answer:
reciprocal of speed of light in vacuum
Explanation:
The average energy stored in the electric field Uᴇ = (1/2) ε₀E²
The average energy stroed in the magnetic field Uв = (1/2) . (B² /μ₀),
According to conservation of energy Ue = Ub
ε₀μ₀ = B² / E²
B / E = √(ε₀μ₀) = 1/C
Related Questions: - Light of wavelength λ from a point source falls on a small circular obstacle
- A solid body rotates about a stationary axis, so that its angular velocity
- In a n-type semiconductor, which of the following statement is true?
- An electromagnetic wave of frequency v = 3.0 MHz passes from vacuum into
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Topics: Electromagnetic Waves
(28)
Subject: Physics
(2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
- Light of wavelength λ from a point source falls on a small circular obstacle
- A solid body rotates about a stationary axis, so that its angular velocity
- In a n-type semiconductor, which of the following statement is true?
- An electromagnetic wave of frequency v = 3.0 MHz passes from vacuum into
- An unpolarised beam of intensity I is incident on a pair of nicols making an angle
Topics: Electromagnetic Waves (28)
Subject: Physics (2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
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