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The ratio of amplitude of magnetic field to the amplitude of electric field for an electromagnetic wave propagating in vacuum is equal to:
Options
(a) The speed of light in vacuum
(b) reciprocal of speed of light in vacuum
(c) the ratio of magnetic permeability to the electric susceptibility of vacuum
(d) unity
Correct Answer:
reciprocal of speed of light in vacuum
Explanation:
The average energy stored in the electric field Uᴇ = (1/2) ε₀E²
The average energy stroed in the magnetic field Uв = (1/2) . (B² /μ₀),
According to conservation of energy Ue = Ub
ε₀μ₀ = B² / E²
B / E = √(ε₀μ₀) = 1/C
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Topics: Electromagnetic Waves
(28)
Subject: Physics
(2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
- Three masses are placed on the x-axis : 300 g at origin, 500 g at x = 40 cm
- When current I is flowing through a conductor, the drift velocity is v.
- In N-type semi-conductor current is due to
- A national roadway bridge over a canal is in the form of an arc of a circle of radius
- If white light is used in Young’s double slit experiment
Topics: Electromagnetic Waves (28)
Subject: Physics (2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
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