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The ratio of amplitude of magnetic field to the amplitude of electric field for an electromagnetic wave propagating in vacuum is equal to:
Options
(a) The speed of light in vacuum
(b) reciprocal of speed of light in vacuum
(c) the ratio of magnetic permeability to the electric susceptibility of vacuum
(d) unity
Correct Answer:
reciprocal of speed of light in vacuum
Explanation:
The average energy stored in the electric field Uᴇ = (1/2) ε₀E²
The average energy stroed in the magnetic field Uв = (1/2) . (B² /μ₀),
According to conservation of energy Ue = Ub
ε₀μ₀ = B² / E²
B / E = √(ε₀μ₀) = 1/C
Related Questions: - The nuclei of which one of the following pairs of nuclei are isotones?
- In semiconductor at a room temperature
- A particle executing SHM with amplitude of 0.1 m. At a certain instant,
- Water falls from a height of 60m at the rate of 15 kg/s to operate a turbine
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Topics: Electromagnetic Waves
(28)
Subject: Physics
(2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
- The nuclei of which one of the following pairs of nuclei are isotones?
- In semiconductor at a room temperature
- A particle executing SHM with amplitude of 0.1 m. At a certain instant,
- Water falls from a height of 60m at the rate of 15 kg/s to operate a turbine
- Dimensions [ML⁻¹T⁻¹] are related with
Topics: Electromagnetic Waves (28)
Subject: Physics (2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
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