| ⇦ | 
| ⇨ |
Young’s modulus of the material of a wire is 18 x 10¹¹ dyne cm⁻². Its value in SI is
Options
(a) 18 x 10¹⁵ Nm⁻²
(b) 18 x 10¹⁰ Nm⁻²
(c) 18 x 10⁹ Nm⁻²
(d) 18 x 10¹² Nm⁻²
Correct Answer:
18 x 10¹⁰ Nm⁻²
Explanation:
1 dyne = 10⁻⁵ Newton
1 cm = 10⁻² m
So, 18 x 10¹¹ x 10⁻⁵ / 10⁻⁴
=18 x 10¹⁰ Nm⁻²
Related Questions: - Two bulbs 60 W and 100 W designed for voltage 220 V are connected in series
- The distance of the closest approach of an alpha particle fired at a nucleus
- The ratio of radii of planets A and B is K₁ and ratio of accelerations
- Dimensional formula for electrical resistance R is given by
- Three solids of masses m₁,m₂ and m₃ are connected with weightless string
Question Type: Memory
(964)
Difficulty Level: Easy
(1008)
Topics: Physical World and Measurement
(103)
Subject: Physics
(2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
- Two bulbs 60 W and 100 W designed for voltage 220 V are connected in series
- The distance of the closest approach of an alpha particle fired at a nucleus
- The ratio of radii of planets A and B is K₁ and ratio of accelerations
- Dimensional formula for electrical resistance R is given by
- Three solids of masses m₁,m₂ and m₃ are connected with weightless string
Question Type: Memory (964)
Difficulty Level: Easy (1008)
Topics: Physical World and Measurement (103)
Subject: Physics (2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
18000+ students are using NEETLab to improve their score. What about you?
Solve Previous Year MCQs, Mock Tests, Topicwise Practice Tests, Identify Weak Topics, Formula Flash cards and much more is available in NEETLab Android App to improve your NEET score.
Share this page with your friends
Leave a Reply