| ⇦ |
| ⇨ |
Young’s modulus of the material of a wire is 18 x 10¹¹ dyne cm⁻². Its value in SI is
Options
(a) 18 x 10¹⁵ Nm⁻²
(b) 18 x 10¹⁰ Nm⁻²
(c) 18 x 10⁹ Nm⁻²
(d) 18 x 10¹² Nm⁻²
Correct Answer:
18 x 10¹⁰ Nm⁻²
Explanation:
1 dyne = 10⁻⁵ Newton
1 cm = 10⁻² m
So, 18 x 10¹¹ x 10⁻⁵ / 10⁻⁴
=18 x 10¹⁰ Nm⁻²
Related Questions: - A wire is stretched under a force. If the wire suddenly snaps the temperature
- The power supplied by a force acting on a particle moving in a straight line
- A force acts on a 3.0 g particle in such a way that the position of the particle
- A bomb of mass 30 kg at rest exploded into two pieces of masses 18 kg
- Rutherford’s α-scattering experiment concludes that
Question Type: Memory
(964)
Difficulty Level: Easy
(1008)
Topics: Physical World and Measurement
(103)
Subject: Physics
(2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
- A wire is stretched under a force. If the wire suddenly snaps the temperature
- The power supplied by a force acting on a particle moving in a straight line
- A force acts on a 3.0 g particle in such a way that the position of the particle
- A bomb of mass 30 kg at rest exploded into two pieces of masses 18 kg
- Rutherford’s α-scattering experiment concludes that
Question Type: Memory (964)
Difficulty Level: Easy (1008)
Topics: Physical World and Measurement (103)
Subject: Physics (2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
18000+ students are using NEETLab to improve their score. What about you?
Solve Previous Year MCQs, Mock Tests, Topicwise Practice Tests, Identify Weak Topics, Formula Flash cards and much more is available in NEETLab Android App to improve your NEET score.
Share this page with your friends

Leave a Reply