When three identical bulbs of 60 W-200 V rating are connected in series to a 200 V

⇦

⇨

When three identical bulbs of 60 W-200 V rating are connected in series to a 200 V supply, the power drawn by them will be

Options

(a) 60 W
(b) 180 W
(c) 10 W
(d) 20 W

Correct Answer:

20 W

Explanation:

In series, Resultant resistance = R₁ + R₂ + R₃ = R + R + R = 3R

Power = V² / R ⇒ 60 = V² / R ⇒ V² = 60 R

Power of combination = P

P = V² / Resistance of combination = 60 / 3 R = 20 W

Related Questions:

1. A coil of resistance 10 Ω and an inductance 5 H is connected to a 100 volt
2. Moment of inertia, along the diameter of a ring is
3. The radius of orbit of a planet is two times that of the earth. The time period
4. Two bodies of mass 1 kg and 3 kg have positive vectors i + 2j + k and -3i -2j + k
5. Reactance of a capacitor of capacitance C µF for A.C freqency (400 / π) Hz is 25 ohm

Topics: Magnetic Effects of Current and Magnetism (167)
Subject: Physics (2479)

---

Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score

18000+ students are using NEETLab to improve their score. What about you?

Solve Previous Year MCQs, Mock Tests, Topicwise Practice Tests, Identify Weak Topics, Formula Flash cards and much more is available in NEETLab Android App to improve your NEET score.

---

Share this page with your friends