| ⇦ | 
| ⇨ |
The motion of a particle along a straight line is described by equation : x= 8 + 12t– t³ where x is in metre and t in second. The retardation of the particle when its velocity becomes zero, is :
Options
(a) 24 ms⁻²
(b) zero
(c) 6ms⁻²
(d) 12 ms⁻²
Correct Answer:
12 ms⁻²
Explanation:
x = 8 + 12t – t³ The final velocity of the particle will be zero, because it retarded.
V= 0 + 12 – 3t² = 0 ⇒ 3t² = 12 ⇒ t = 2 sec
Now the retardation a = dv/ dt = 0 – 6t
a [ t= 2] = – 12 m/s²
retardation = 12 m/s²
Related Questions: - Given the value of Rydberg constant is 10⁷ m⁻¹, the wave number of the last line
- A transformer is used to light a 100 W and 110 V lamp from a 220 V mains.
- Two bulbs 40 watt and 60 watt and rated voltage 240 V are connected in series
- A charge Q is enclosed by a Gaussian spherical surface of radius R
- A uniform plank of Young’s modulus Y is moved over a smooth horizontal surface
Topics: Motion in Straight Line
(93)
Subject: Physics
(2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
- Given the value of Rydberg constant is 10⁷ m⁻¹, the wave number of the last line
- A transformer is used to light a 100 W and 110 V lamp from a 220 V mains.
- Two bulbs 40 watt and 60 watt and rated voltage 240 V are connected in series
- A charge Q is enclosed by a Gaussian spherical surface of radius R
- A uniform plank of Young’s modulus Y is moved over a smooth horizontal surface
Topics: Motion in Straight Line (93)
Subject: Physics (2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
18000+ students are using NEETLab to improve their score. What about you?
Solve Previous Year MCQs, Mock Tests, Topicwise Practice Tests, Identify Weak Topics, Formula Flash cards and much more is available in NEETLab Android App to improve your NEET score.
Share this page with your friends
Leave a Reply