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The motion of a particle along a straight line is described by equation : x= 8 + 12t– t³ where x is in metre and t in second. The retardation of the particle when its velocity becomes zero, is :
Options
(a) 24 ms⁻²
(b) zero
(c) 6ms⁻²
(d) 12 ms⁻²
Correct Answer:
12 ms⁻²
Explanation:
x = 8 + 12t – t³ The final velocity of the particle will be zero, because it retarded.
V= 0 + 12 – 3t² = 0 ⇒ 3t² = 12 ⇒ t = 2 sec
Now the retardation a = dv/ dt = 0 – 6t
a [ t= 2] = – 12 m/s²
retardation = 12 m/s²
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Topics: Motion in Straight Line
(93)
Subject: Physics
(2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
- A 220 volt and 1000 watt bulb is connected across a 110 volt mains supply.
- The component of vector A=2i+3j along the vector i+j is
- A speeding motorcyclist sees traffic jam ahead him. He slows down to 36 km per hour
- A particle moves in a circle of radius 5 cm with constant speed and time period
- If two vectors are equal in magnitude and their resultant is also equal in magnitude
Topics: Motion in Straight Line (93)
Subject: Physics (2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
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