| ⇦ | 
| ⇨ |
An alternating voltage of 220 V, 50 Hz frequency is applied across a capacitor of capacitance 2 μF. The impedence of the circuit is
Options
(a) π/5000
(b) 1000/π
(c) 500π
(d) 5000/π
Correct Answer:
5000/π
Explanation:
Impedance of a capacitor is Xc = 1 / ωC
Xc = 1 / 2πfC = 1 / (2π × 50 × 2 × 10⁻⁶) = 5000 / π
Related Questions: - If by mistake voltmeter is connected in series and ammeter in parallel then
- Excitation energy of a hydrogen like ion, in its first excitation state, is 40.8 eV.
- Two masses of 9 g and 6 g are connected with a string which is passing over a frictionless
- A wire of one metre length carries a constant current. The wire is bent to form
- A wire having resistance 12Ω is bent in the form of an equilateral triangle.
Topics: Alternating Current
(96)
Subject: Physics
(2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
- If by mistake voltmeter is connected in series and ammeter in parallel then
- Excitation energy of a hydrogen like ion, in its first excitation state, is 40.8 eV.
- Two masses of 9 g and 6 g are connected with a string which is passing over a frictionless
- A wire of one metre length carries a constant current. The wire is bent to form
- A wire having resistance 12Ω is bent in the form of an equilateral triangle.
Topics: Alternating Current (96)
Subject: Physics (2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
18000+ students are using NEETLab to improve their score. What about you?
Solve Previous Year MCQs, Mock Tests, Topicwise Practice Tests, Identify Weak Topics, Formula Flash cards and much more is available in NEETLab Android App to improve your NEET score.
Share this page with your friends
Leave a Reply