| ⇦ | 
| ⇨ |
An alternating voltage of 220 V, 50 Hz frequency is applied across a capacitor of capacitance 2 μF. The impedence of the circuit is
Options
(a) π/5000
(b) 1000/π
(c) 500π
(d) 5000/π
Correct Answer:
5000/π
Explanation:
Impedance of a capacitor is Xc = 1 / ωC
Xc = 1 / 2πfC = 1 / (2π × 50 × 2 × 10⁻⁶) = 5000 / π
Related Questions: - A source of sound S emitting waves of frequency 100 Hz and an observer
- Magnetism of a magnet is due to
- A beam of electron passes undeflected through mutually perpendicular
- Three capacitors 3μF,6μF and 6μF are connected in series to a source of 120V.
- A body of mass 0.5 kg travels in a straight line with velocity v=a x³/², where
Topics: Alternating Current
(96)
Subject: Physics
(2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
- A source of sound S emitting waves of frequency 100 Hz and an observer
- Magnetism of a magnet is due to
- A beam of electron passes undeflected through mutually perpendicular
- Three capacitors 3μF,6μF and 6μF are connected in series to a source of 120V.
- A body of mass 0.5 kg travels in a straight line with velocity v=a x³/², where
Topics: Alternating Current (96)
Subject: Physics (2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
18000+ students are using NEETLab to improve their score. What about you?
Solve Previous Year MCQs, Mock Tests, Topicwise Practice Tests, Identify Weak Topics, Formula Flash cards and much more is available in NEETLab Android App to improve your NEET score.
Share this page with your friends
Leave a Reply