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An alternating voltage of 220 V, 50 Hz frequency is applied across a capacitor of capacitance 2 μF. The impedence of the circuit is
Options
(a) π/5000
(b) 1000/π
(c) 500π
(d) 5000/π
Correct Answer:
5000/π
Explanation:
Impedance of a capacitor is Xc = 1 / ωC
Xc = 1 / 2πfC = 1 / (2π × 50 × 2 × 10⁻⁶) = 5000 / π
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Topics: Alternating Current
(96)
Subject: Physics
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