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An alternating voltage of 220 V, 50 Hz frequency is applied across a capacitor of capacitance 2 μF. The impedence of the circuit is
Options
(a) π/5000
(b) 1000/π
(c) 500π
(d) 5000/π
Correct Answer:
5000/π
Explanation:
Impedance of a capacitor is Xc = 1 / ωC
Xc = 1 / 2πfC = 1 / (2π × 50 × 2 × 10⁻⁶) = 5000 / π
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Topics: Alternating Current
(96)
Subject: Physics
(2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
- If in an experiment for determination of velocity of sound by resonance tube
- Two identical long conducting wires AOB and COD are placed at right angle
- A force of 10 newton acts on a body of mass 20 kg for 10 seconds. Change in its momentum
- Three resistances 2Ω, 3Ω and 4Ω are connected in parallel. The ratio of currents passing
- A meter stick of mass 400 g is pivoted at one end and displaced through an angle 60°.
Topics: Alternating Current (96)
Subject: Physics (2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
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