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When light of wavelength 300 nm falls on a photoelectric emitter, photoelectrons are liberated. For another emitter, light of wavelength 600 nm is sufficient for liberating photoelectrons. The ratio of the work function of the two emitters is
Options
(a) (1:2)
(b) (2:1)
(c) (4:1)
(d) (1:4)
Correct Answer:
(2:1)
Explanation:
No explanation available. Be the first to write the explanation for this question by commenting below.
Related Questions: - The number of photo electrons emitted for light of a frequency v
- An aeroplane flies 400m due to North and then 300m due to south and then flies
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Topics: Dual Nature of Matter and Radiation
(150)
Subject: Physics
(2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
- The number of photo electrons emitted for light of a frequency v
- An aeroplane flies 400m due to North and then 300m due to south and then flies
- A ray enters a glass sphere of refractive index μ=√3 at an angle of incidence of 60⁰
- Which of the following is true for elastic potential energy density?
- The surface tension of a liquid is 5 newton per metre. If a film
Topics: Dual Nature of Matter and Radiation (150)
Subject: Physics (2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
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