| ⇦ | ⇨ |
A p-n photodiode is fabricated from a semiconductor with a band gap of 2.5 eV. It can be detect a signal of wavelength
Options
(a) 4000 nm
(b) 6000 nm
(c) 4000Å
(d) 6000Å
Correct Answer:
4000Å
Explanation:
λₘₐₓ = hc / E
= 6.6 x 10⁻³⁴ x 3 x 10⁸ / 2.5 x 1.6 x 10⁻¹⁹ = 5000Å
The wavelength detected by photodiode should be less than λₘₐₓ. Hence it can detect a signal of wavelength 4000Å.
Related Questions: - What is the energy of He⁺ electron in first orbit?
- The thermo e.m.f. E in volts of a certain thermocouple is found to vary
- The magnetic lines of force inside a bar magnet
- If the electric field lines is flowing along axis of a cylinder, then the flux
- A transverse wave is represented by y = a sin (?t – kx)
Topics: Electronic Devices
(124)
Subject: Physics
(2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
- What is the energy of He⁺ electron in first orbit?
- The thermo e.m.f. E in volts of a certain thermocouple is found to vary
- The magnetic lines of force inside a bar magnet
- If the electric field lines is flowing along axis of a cylinder, then the flux
- A transverse wave is represented by y = a sin (?t – kx)
Topics: Electronic Devices (124)
Subject: Physics (2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
18000+ students are using NEETLab to improve their score. What about you?
Solve Previous Year MCQs, Mock Tests, Topicwise Practice Tests, Identify Weak Topics, Formula Flash cards and much more is available in NEETLab Android App to improve your NEET score.
Share this page with your friends

Leave a Reply