| ⇦ | 
| ⇨ |
A solenoid of length l metre has self inductance L henry. If number of turns are doubled, its self inductance
Options
(a) Becomes 2 L henry
(b) Becomes 4 L henry
(c) Remains same
(d) Becomes L/√2 henry
Correct Answer:
Becomes 4 L henry
Explanation:
No explanation available. Be the first to write the explanation for this question by commenting below.
Related Questions: - The energy released in the fission of 1 kg of ₉₂U²³⁵ is (energy per fission = 200 MeV)
- A transistor is working in common emitter mode. Its amplification factor is 80
- A nucleus of uranium decays at rest into nuclei of thrrium and helium. Then
- Mass and diameter of a ring is 2 kg and 1 m respectively. The moment of inertia
- A charge of 40 µC is given to a capacitor having capacitance C=10 µF
Topics: Electromagnetic Induction
(76)
Subject: Physics
(2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
- The energy released in the fission of 1 kg of ₉₂U²³⁵ is (energy per fission = 200 MeV)
- A transistor is working in common emitter mode. Its amplification factor is 80
- A nucleus of uranium decays at rest into nuclei of thrrium and helium. Then
- Mass and diameter of a ring is 2 kg and 1 m respectively. The moment of inertia
- A charge of 40 µC is given to a capacitor having capacitance C=10 µF
Topics: Electromagnetic Induction (76)
Subject: Physics (2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
18000+ students are using NEETLab to improve their score. What about you?
Solve Previous Year MCQs, Mock Tests, Topicwise Practice Tests, Identify Weak Topics, Formula Flash cards and much more is available in NEETLab Android App to improve your NEET score.
Share this page with your friends
The formula to be used here is that :L= N^2(A)/l.
now ,N=2.
therefore, L’=2^2(A)/l
=> L’/L = 4/1
=> L’= 4L henry