| ⇦ |
| ⇨ |
When a sound wave of wavelength λ is propagating in a medium, the maximum velocity of the particle is equal to the wave velocity. The amplitude of wave is
Options
(a) λ
(b) λ/2
(c) λ/2π
(d) λ/4π
Correct Answer:
λ/2π
Explanation:
Maximum particle velocity (vₚ)ₘₐₓ = aω
where a is the amplitude of the wave and ω is the angular frequency
Wave velocity, v = λʋ
where λ is the wavelength of a wave and ʋ is a frequency of a wave.
Given : vₚ = v .·. aω = λʋ or a × 2πʋ = λʋ or a = λ/2π
Related Questions: - The fundamental frequency of a closed organ pipe of length 20 cm is equal to the second
- A wheel has angular acceleration of 3.0 rad/sec² and an initial angular speed
- An interference pattern was made by using red light. If the red light
- A body starts from rest, what is the ratio of the distance travelled by the body
- A thermodynamic system undergoes cyclic process ABCDA as shown in figure
Topics: Waves
(80)
Subject: Physics
(2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
- The fundamental frequency of a closed organ pipe of length 20 cm is equal to the second
- A wheel has angular acceleration of 3.0 rad/sec² and an initial angular speed
- An interference pattern was made by using red light. If the red light
- A body starts from rest, what is the ratio of the distance travelled by the body
- A thermodynamic system undergoes cyclic process ABCDA as shown in figure
Topics: Waves (80)
Subject: Physics (2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
18000+ students are using NEETLab to improve their score. What about you?
Solve Previous Year MCQs, Mock Tests, Topicwise Practice Tests, Identify Weak Topics, Formula Flash cards and much more is available in NEETLab Android App to improve your NEET score.
Share this page with your friends

Leave a Reply