| ⇦ | 
| ⇨ |
When a sound wave of wavelength λ is propagating in a medium, the maximum velocity of the particle is equal to the wave velocity. The amplitude of wave is
Options
(a) λ
(b) λ/2
(c) λ/2π
(d) λ/4π
Correct Answer:
λ/2π
Explanation:
Maximum particle velocity (vₚ)ₘₐₓ = aω
where a is the amplitude of the wave and ω is the angular frequency
Wave velocity, v = λʋ
where λ is the wavelength of a wave and ʋ is a frequency of a wave.
Given : vₚ = v .·. aω = λʋ or a × 2πʋ = λʋ or a = λ/2π
Related Questions: - Two point charge +9e and +e are at 16 cm away from each other.
- Ionization potential of hydrogen atom is 13.6 eV. Hydrogen atoms in the ground state
- The mean free path of molecules of a gas,(radius ‘r’) is inversely proportional to
- The acceleration of an electron in an electric field of magnitude 50 V/cm,
- In R-L-C series circuit, the potential differences across each element is 20 V.
Topics: Waves
(80)
Subject: Physics
(2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
- Two point charge +9e and +e are at 16 cm away from each other.
- Ionization potential of hydrogen atom is 13.6 eV. Hydrogen atoms in the ground state
- The mean free path of molecules of a gas,(radius ‘r’) is inversely proportional to
- The acceleration of an electron in an electric field of magnitude 50 V/cm,
- In R-L-C series circuit, the potential differences across each element is 20 V.
Topics: Waves (80)
Subject: Physics (2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
18000+ students are using NEETLab to improve their score. What about you?
Solve Previous Year MCQs, Mock Tests, Topicwise Practice Tests, Identify Weak Topics, Formula Flash cards and much more is available in NEETLab Android App to improve your NEET score.
Share this page with your friends
Leave a Reply