| ⇦ | 
| ⇨ |
When 1 mol of gas is heated at constant volume, temperature is raised from 298 to 308 K. Heat supplied to the gas is 500J. Then which statement is correct
Options
(a) q = w = 500 J,ΔU = 0
(b) q = ΔU = 500 J,W = 0
(c) q = w = 500 J ,ΔU = 0
(d) ΔU = 0, q = w = -500J
Correct Answer:
q = ΔU = 500 J,W = 0
Explanation:
We known that ΔH = ΔE + PV
ΔH = ΔE + P Δ V + V Δ P =0
When ΔV = 0; w = 0. Therefore ΔH = ΔE + PΔV
ΔH = ΔE + 0 or ΔH = ΔE.
As ΔE = q + w , ΔE = q.
In the present problem, ΔH = 500J,
ΔV = ΔE = 500 J,q = 500 J, w = 0.
Related Questions: - Which of the following contains amino group
- 6.02 x 10²° molecules of urea are present in 100 mL of its solution
- The complex [CoF₆]⁴⁻ is
- A buffer solution contains 0.1 M of acetic acid and 0.1 M of sodium acetate.
- The rate constant of the reaction A → B is 0.6 ˣ 10⁻³ mol per second.
Topics: Thermodynamics
(179)
Subject: Chemistry
(2512)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
- Which of the following contains amino group
- 6.02 x 10²° molecules of urea are present in 100 mL of its solution
- The complex [CoF₆]⁴⁻ is
- A buffer solution contains 0.1 M of acetic acid and 0.1 M of sodium acetate.
- The rate constant of the reaction A → B is 0.6 ˣ 10⁻³ mol per second.
Topics: Thermodynamics (179)
Subject: Chemistry (2512)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
18000+ students are using NEETLab to improve their score. What about you?
Solve Previous Year MCQs, Mock Tests, Topicwise Practice Tests, Identify Weak Topics, Formula Flash cards and much more is available in NEETLab Android App to improve your NEET score.
Share this page with your friends
Leave a Reply