| ⇦ |
| ⇨ |
Enthalpy of CH₄ + ¹/² O₂ → CH₃OH is negative. If enthalpy of combustion of CH₄ and CH₃OH are x and y respectively. Then which relation is correct
Options
(a) x > y
(b) x < y
(c) x = y
(d) x > y
Correct Answer:
x < y
Explanation:
CH₄ + 1/2 O₂ → CH₃OH, ΔH = x -y; Given ΔH = negative. hence, x-y < 0, or n < y.
Related Questions: - Which of the following C-H bonds has lowest bond dissociation energy
- Rectified spirit has ethanol
- The hybridised state of N in R₂NH is
- Which of the following statement about the member of any one homologous series
- The correct order of decreasing acidic nature of H₂O,ROH,CH≡CH and NH₃ is
Topics: Thermodynamics
(179)
Subject: Chemistry
(2512)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
- Which of the following C-H bonds has lowest bond dissociation energy
- Rectified spirit has ethanol
- The hybridised state of N in R₂NH is
- Which of the following statement about the member of any one homologous series
- The correct order of decreasing acidic nature of H₂O,ROH,CH≡CH and NH₃ is
Topics: Thermodynamics (179)
Subject: Chemistry (2512)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
18000+ students are using NEETLab to improve their score. What about you?
Solve Previous Year MCQs, Mock Tests, Topicwise Practice Tests, Identify Weak Topics, Formula Flash cards and much more is available in NEETLab Android App to improve your NEET score.
Share this page with your friends

Leave a Reply