| ⇦ | 
| ⇨ |
When 1 kg of ice at 0⁰C melts to water at 0⁰C, the resulting change in its entropy, taking latent heat of ice to be 80 cal/⁰C, is
Options
(a) 273 cal/K
(b) 8 x 104 cal/K
(c) 80 cal/K
(d) 293 cal/K
Correct Answer:
293 cal/K
Explanation:
Change in entropy is given by
dS = dQ / T or ∆S = ∆Q / T = mLf / 273
∆S = 1000 x 80 / 273 = 293cal / K
Related Questions: - Photocells convert
- A black hole is an object whose gravitational field is so strong that even light
- In a transistor, the value of βis 100, then the value of α will be
- The radius of orbit of a planet is two times that of the earth. The time period
- A p-n-p transistor is used in common emitter mode in an amplifier circuit.
Topics: Thermodynamics
(179)
Subject: Physics
(2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
- Photocells convert
- A black hole is an object whose gravitational field is so strong that even light
- In a transistor, the value of βis 100, then the value of α will be
- The radius of orbit of a planet is two times that of the earth. The time period
- A p-n-p transistor is used in common emitter mode in an amplifier circuit.
Topics: Thermodynamics (179)
Subject: Physics (2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
18000+ students are using NEETLab to improve their score. What about you?
Solve Previous Year MCQs, Mock Tests, Topicwise Practice Tests, Identify Weak Topics, Formula Flash cards and much more is available in NEETLab Android App to improve your NEET score.
Share this page with your friends
Leave a Reply