| ⇦ |
| ⇨ |
When 1 kg of ice at 0⁰C melts to water at 0⁰C, the resulting change in its entropy, taking latent heat of ice to be 80 cal/⁰C, is
Options
(a) 273 cal/K
(b) 8 x 104 cal/K
(c) 80 cal/K
(d) 293 cal/K
Correct Answer:
293 cal/K
Explanation:
Change in entropy is given by
dS = dQ / T or ∆S = ∆Q / T = mLf / 273
∆S = 1000 x 80 / 273 = 293cal / K
Related Questions: - A black body at 227⁰C radiates heat at the rate of 7cals/cm²s. At a temperature
- If radius of the ₁₃Al²⁷ nucleus is taken to be Rᴀı, then the radius of ₅₃Te¹²⁵ nucleus
- The diameter of the eye ball of a normal eye is about 2.5 cm. The power of the eye
- A train is moving along a straight path with uniform acceleration
- In the Young’s double slit experiment, a point P on the central bright fringe
Topics: Thermodynamics
(179)
Subject: Physics
(2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
- A black body at 227⁰C radiates heat at the rate of 7cals/cm²s. At a temperature
- If radius of the ₁₃Al²⁷ nucleus is taken to be Rᴀı, then the radius of ₅₃Te¹²⁵ nucleus
- The diameter of the eye ball of a normal eye is about 2.5 cm. The power of the eye
- A train is moving along a straight path with uniform acceleration
- In the Young’s double slit experiment, a point P on the central bright fringe
Topics: Thermodynamics (179)
Subject: Physics (2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
18000+ students are using NEETLab to improve their score. What about you?
Solve Previous Year MCQs, Mock Tests, Topicwise Practice Tests, Identify Weak Topics, Formula Flash cards and much more is available in NEETLab Android App to improve your NEET score.
Share this page with your friends

Leave a Reply