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**The ratio of the weight of a man in a stationary lift and when it is moving downwards with uniform acceleration a is 3:2,then the value of a is **

### Options

(a) 3/2 g

(b) g/3

(c) g

(d) 2/3g

### Correct Answer:

g/3

### Explanation:

Weight when stationary = mg

Weight when moving downwards = m(g-a)

3/2 = mg/m(g-a)

3g – 3a = 2g

⇒ a = g/3

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Topics: Laws of Motion
(103)

Subject: Physics
(2479)

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