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The ratio of the weight of a man in a stationary lift and when it is moving downwards with uniform acceleration a is 3:2,then the value of a is
Options
(a) 3/2 g
(b) g/3
(c) g
(d) 2/3g
Correct Answer:
g/3
Explanation:
Weight when stationary = mg
Weight when moving downwards = m(g-a)
3/2 = mg/m(g-a)
3g – 3a = 2g
⇒ a = g/3
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Topics: Laws of Motion
(103)
Subject: Physics
(2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
- A voltmeter of range 2 V and resistance 300Ω cannot be converted into ammeter
- A radio isotope X with a half life 1.4 x 10⁹ years decays to Y which is stable
- If energy(E), velocity(V) and time(T) are chosen as fundamental quantities,
- A radioactive substance emits n beta particles in the first 2 s and 0.5 n beta
- A resistance R draws power P when connected to an AC source. If an inductance
Topics: Laws of Motion (103)
Subject: Physics (2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
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