| ⇦ | 
| ⇨ |
Two closed organ pipes when sounded simultaneously give 4 beats/second. If longer pipe has a length of 1m, then length of shorter pipe will be (v=300 m/s)
Options
(a) 185.5 cm
(b) 94.9 cm
(c) 90 cm
(d) 80 cm
Correct Answer:
94.9 cm
Explanation:
n₂ – n₁ = 4, For closed pipe, n = V/4l
(V/4l₂) – (V/4l₁) = 4 ⇒ (V/4l₂) – (V/4×1) = 4
(300/4l₂) – (300/4) = 4 ⇒ 75/l₂ = 4 + 75 ⇒ 75/l₂ = 79
⇒ l₂ = (75/79) met = (75×100)/79 = 94.9 cm.
Related Questions: - A parallel plate capacitor of a capacitance 1 pF has seperation between the plates
- 180⁰ phase difference is obtained when light ray is reflected from
- A cycle wheel of radius 4 m completes one revolution in two seconds. Then acceleration
- The temperature coefficient of the resistance of a wire is 0.00125 per ⁰C.
- Two straight wires each 10cm long are parallel to one another and seperated by 2 cm.
Topics: Waves
(80)
Subject: Physics
(2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
- A parallel plate capacitor of a capacitance 1 pF has seperation between the plates
- 180⁰ phase difference is obtained when light ray is reflected from
- A cycle wheel of radius 4 m completes one revolution in two seconds. Then acceleration
- The temperature coefficient of the resistance of a wire is 0.00125 per ⁰C.
- Two straight wires each 10cm long are parallel to one another and seperated by 2 cm.
Topics: Waves (80)
Subject: Physics (2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
18000+ students are using NEETLab to improve their score. What about you?
Solve Previous Year MCQs, Mock Tests, Topicwise Practice Tests, Identify Weak Topics, Formula Flash cards and much more is available in NEETLab Android App to improve your NEET score.
Share this page with your friends
Leave a Reply