| ⇦ | 
| ⇨ |
What is the voltage gain in a common-emiiter amplifier, when input resistance is 4 Ω and load resistance is 24 Ω? Take β=0.6
Options
(a) 3.6
(b) 4.8
(c) 2.4
(d) 1.2
Correct Answer:
3.6
Explanation:
Input resistance Rᵢ = 4Ω
Load resistance Rʟ = 24Ω
Resistance gain = Rʟ / Rᵢ = 24Ω / 4Ω = 6
Current gain β = 0.6
Voltage gain = Current gain x Resistance gain
= 0.6 x 6 = 3.6
Related Questions: - The magnetic susceptibility of a material of a rod is 299. Permeability of vacuum
- The dimension of 1/2ε₀E², where ε₀ is permittivity of free space and E is electric field
- If the focal length of objective lens is increased, then magnifying power of
- A body of mass 2 kg is moved by a force F=3x where x is the distance covered.
- A proton and an alpha particle both enter a region of uniform magnetic field B,
Topics: Electronic Devices
(124)
Subject: Physics
(2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
- The magnetic susceptibility of a material of a rod is 299. Permeability of vacuum
- The dimension of 1/2ε₀E², where ε₀ is permittivity of free space and E is electric field
- If the focal length of objective lens is increased, then magnifying power of
- A body of mass 2 kg is moved by a force F=3x where x is the distance covered.
- A proton and an alpha particle both enter a region of uniform magnetic field B,
Topics: Electronic Devices (124)
Subject: Physics (2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
18000+ students are using NEETLab to improve their score. What about you?
Solve Previous Year MCQs, Mock Tests, Topicwise Practice Tests, Identify Weak Topics, Formula Flash cards and much more is available in NEETLab Android App to improve your NEET score.
Share this page with your friends
Leave a Reply