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What is the voltage gain in a common-emiiter amplifier, when input resistance is 4 Ω and load resistance is 24 Ω? Take β=0.6
Options
(a) 3.6
(b) 4.8
(c) 2.4
(d) 1.2
Correct Answer:
3.6
Explanation:
Input resistance Rᵢ = 4Ω
Load resistance Rʟ = 24Ω
Resistance gain = Rʟ / Rᵢ = 24Ω / 4Ω = 6
Current gain β = 0.6
Voltage gain = Current gain x Resistance gain
= 0.6 x 6 = 3.6
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Topics: Electronic Devices
(124)
Subject: Physics
(2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
- Perfectly black body radiates the energy 18 J/s at 300K. Another ordinary body of e=0.8
- Two pendulums A and B are oscillating simultaneously with time period
- A capacitor is charged to 200 volt. It has a charge of 0.1 coulomb.
- Two wires of the same dimensions but resistivities p1 and p2 are connected in series
- The initial rate of increase of current, when a battery of emf 6 V is connected
Topics: Electronic Devices (124)
Subject: Physics (2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
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