| ⇦ |
| ⇨ |
What is the voltage gain in a common-emiiter amplifier, when input resistance is 4 Ω and load resistance is 24 Ω? Take β=0.6
Options
(a) 3.6
(b) 4.8
(c) 2.4
(d) 1.2
Correct Answer:
3.6
Explanation:
Input resistance Rᵢ = 4Ω
Load resistance Rʟ = 24Ω
Resistance gain = Rʟ / Rᵢ = 24Ω / 4Ω = 6
Current gain β = 0.6
Voltage gain = Current gain x Resistance gain
= 0.6 x 6 = 3.6
Related Questions: - On heating a ferromagnetic substance above curie temperature
- A particle moves a distance x in time t according to equation x = (t + 5)⁻¹
- Which of the following phenomenon exhibited the particle nature of light?
- In the middle of the depletion layer of a reverse-biased P-N junction, the
- Under the action of a force F=cx, the position of a body changes from 0 to x.The work done
Topics: Electronic Devices
(124)
Subject: Physics
(2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
- On heating a ferromagnetic substance above curie temperature
- A particle moves a distance x in time t according to equation x = (t + 5)⁻¹
- Which of the following phenomenon exhibited the particle nature of light?
- In the middle of the depletion layer of a reverse-biased P-N junction, the
- Under the action of a force F=cx, the position of a body changes from 0 to x.The work done
Topics: Electronic Devices (124)
Subject: Physics (2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
18000+ students are using NEETLab to improve their score. What about you?
Solve Previous Year MCQs, Mock Tests, Topicwise Practice Tests, Identify Weak Topics, Formula Flash cards and much more is available in NEETLab Android App to improve your NEET score.
Share this page with your friends

Leave a Reply