| ⇦ |
| ⇨ |
A particle moves a distance x in time t according to equation x = (t + 5)⁻¹. The acceleration of particle is proportional to
Options
(a) (velocity)^3/2
(b) (distance)^2
(c) (distance) ^ –2
(d) (velocity) ^ 2/3
Correct Answer:
(velocity)^3/2
Explanation:
x = 1 / t + 5
v = dx / dt = -1 / (t + 5)²
a = d²x / dt² = 2 / (t + 5)³ = 2x³
Now, 1 / (t + 5) ∞ v½
1 / (t + 5)³ ∞ v³/² ∞ a
Related Questions: - Two points are located at a distance of 10 m and 15 m from the source of oscillation
- A stone of mass 1kg is tied to a string 4m long and is rotated at constant speed
- The radius of the convex surface of a plano-convex lens is 20 cm and the refractive index
- A uniform electric field and uniform magnetic field are acting along the same
- The decay constant of a radio isotope is λ. If A₁ and A₂ are its activities at time
Topics: Motion in Straight Line
(93)
Subject: Physics
(2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
- Two points are located at a distance of 10 m and 15 m from the source of oscillation
- A stone of mass 1kg is tied to a string 4m long and is rotated at constant speed
- The radius of the convex surface of a plano-convex lens is 20 cm and the refractive index
- A uniform electric field and uniform magnetic field are acting along the same
- The decay constant of a radio isotope is λ. If A₁ and A₂ are its activities at time
Topics: Motion in Straight Line (93)
Subject: Physics (2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
18000+ students are using NEETLab to improve their score. What about you?
Solve Previous Year MCQs, Mock Tests, Topicwise Practice Tests, Identify Weak Topics, Formula Flash cards and much more is available in NEETLab Android App to improve your NEET score.
Share this page with your friends

Thankyou