Two waves are represented by the equations y₁ = a sin (?t + kx + 0.57) m

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Two waves are represented by the equations y₁ = a sin (?t + kx + 0.57) m and y₂ = a cos (?t + kx) m, where x is in meter and t in sec. The phase difference between them is

Options

(a) 1.0 radian
(b) 1.25 radian
(c) 1.57 radian
(d) 0.57 radian

Correct Answer:

1.0 radian

Explanation:

Here, y₁ = a sin (?t + kx + 0.57 )
and y₂ = a cos (?t + kx )
= a sin [π/2 + (?t – kx)
Phase difference, ∆? = ?￢ﾂﾂ – ?￢ﾂﾁ
= π/2 – 0.57 = 3.14 / 2 – 0.57 = 1.57 – 0.57
1 radian

Related Questions:

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Topics: Waves (80)
Subject: Physics (2479)

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