⇦ | ![]() | ⇨ |
Two waves are represented by the equations y₁ = a sin (?t + kx + 0.57) m and y₂ = a cos (?t + kx) m, where x is in meter and t in sec. The phase difference between them is
Options
(a) 1.0 radian
(b) 1.25 radian
(c) 1.57 radian
(d) 0.57 radian
Correct Answer:
1.0 radian
Explanation:
Here, y₁ = a sin (?t + kx + 0.57 )
and y₂ = a cos (?t + kx )
= a sin [π/2 + (?t – kx)
Phase difference, ∆? = ?¬ツツ – ?¬ツチ
= π/2 – 0.57 = 3.14 / 2 – 0.57 = 1.57 – 0.57
1 radian
Related Questions:
- For the radioactive nuclei that undergo either α or β decay, which one
- Two bodies of masses m₁ and m₂ are initially at rest at infinite distance apart
- A stone tied to the end of a string of 1 m long is whirled in a horizontal circle
- A boy standing at top of a tower of 20 m height drops a stone
- If h is planck’s constant and λ is wavelength, h/λ has dimensions of
Topics: Waves
(80)
Subject: Physics
(2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
18000+ students are using NEETLab to improve their score. What about you?
Solve Previous Year MCQs, Mock Tests, Topicwise Practice Tests, Identify Weak Topics, Formula Flash cards and much more is available in NEETLab Android App to improve your NEET score.
Share this page with your friends
Leave a Reply