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A radioactive substance decays to 1/16th of its initial activity in 40 days. The half-life of the radioactive substance expressed in days is
Options
(a) 2.5
(b) 5
(c) 10
(d) 20
Correct Answer:
10
Explanation:
N/N₀ = (1/2)ⁿ
(1/16) = (1/2)ⁿ
n = 4
Half life = t / n = 40 / 4 = 10 day
Related Questions: - A solenoid 1.5 m long and 0.4 cm in diameter possesses 10 turns per cm length
- The velocity of a particle performing simple harmonic motion, when it passes
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Topics: Radioactivity
(83)
Subject: Physics
(2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
- A solenoid 1.5 m long and 0.4 cm in diameter possesses 10 turns per cm length
- The velocity of a particle performing simple harmonic motion, when it passes
- A ray of light is incident at an angle of incidence i, on one face of a prism
- Which of the following will be σ if Y=2.4 η?
- If we study the vibration of a pipe open at both ends
Topics: Radioactivity (83)
Subject: Physics (2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
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