| ⇦ | 
| ⇨ |
A tuning fork of frequency 512 Hz makes 4 beats per second with the vibrating string of a piano. The beat frequency decreases to 2 beats per sec when the tension in the piano string is slightly increased. The frequency of the piano string before increasing the tension was
Options
(a) 510 Hz
(b) 514 Hz
(c) 516 Hz
(d) 508 Hz
Correct Answer:
508 Hz
Explanation:
The frequency of the piano string = 512+-4 = 516 or 508. When the tension is increased, beat frequency decreases to 2, it means that frequency of othe string is 508 as frequency of string increases with tension.
Related Questions: - A small part of the rim of a fly wheel breaks off while it is rotating at a constant
- When 10¹⁹elecrons are removed from a neutral metal plate through some process,
- The breaking stress of a wire depends upon
- A galvanometer coil has a resistance of 15 ohm and gives full scale deflection
- The lowest frequency of light that will cause the emission of photoelectrons
Topics: Waves
(80)
Subject: Physics
(2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
- A small part of the rim of a fly wheel breaks off while it is rotating at a constant
- When 10¹⁹elecrons are removed from a neutral metal plate through some process,
- The breaking stress of a wire depends upon
- A galvanometer coil has a resistance of 15 ohm and gives full scale deflection
- The lowest frequency of light that will cause the emission of photoelectrons
Topics: Waves (80)
Subject: Physics (2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
18000+ students are using NEETLab to improve their score. What about you?
Solve Previous Year MCQs, Mock Tests, Topicwise Practice Tests, Identify Weak Topics, Formula Flash cards and much more is available in NEETLab Android App to improve your NEET score.
Share this page with your friends
Leave a Reply