⇦ | ![]() | ⇨ |
Two simple harmonic motions of angular frequency 100 and 1000 rad s⁻¹ have the same displacement amplitude. The ratio of other maximum accelerations is:
Options
(a) 1 : 10
(b) 1 : 10²
(c) 1 : 10³
(d) 1 : 10⁴
Correct Answer:
1 : 10²
Explanation:
Maximum acceleration of a particle in the simple harmonic motion is directly proportional to the square of angular frequency i.e., a(max)= – w ² A
As A remains same, we can say
a₁ / a₂ = w₁² / w₂² = (100)² / (1000)² = 1 / 100
⇒ a₁ : a₂ = 1 : 10²
Related Questions:
- The radius of orbit of a planet is two times that of the earth. The time period
- A force of 5 N is acting on an object. Displacement of object is 10 m and the work done
- Two cells, having the same e.m.f. are connected in series through an external resistance
- Monochromatic radiation emitted when electron on hydrogen atom
- An electric dipole of length 1 cm is placed with the axis making an angle of 30⁰
Topics: Oscillations
(58)
Subject: Physics
(2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
18000+ students are using NEETLab to improve their score. What about you?
Solve Previous Year MCQs, Mock Tests, Topicwise Practice Tests, Identify Weak Topics, Formula Flash cards and much more is available in NEETLab Android App to improve your NEET score.
Share this page with your friends
Leave a Reply