| ⇦ | 
| ⇨ |
Two simple harmonic motions of angular frequency 100 and 1000 rad s⁻¹ have the same displacement amplitude. The ratio of other maximum accelerations is:
Options
(a) 1 : 10
(b) 1 : 10²
(c) 1 : 10³
(d) 1 : 10⁴
Correct Answer:
1 : 10²
Explanation:
Maximum acceleration of a particle in the simple harmonic motion is directly proportional to the square of angular frequency i.e., a(max)= – w ² A
As A remains same, we can say
a₁ / a₂ = w₁² / w₂² = (100)² / (1000)² = 1 / 100
⇒ a₁ : a₂ = 1 : 10²
Related Questions: - When ultraviolet rays are incident on metal plate, then photoelectric effect
- 1 a.m.u. is equivalent to
- The atomic number of the most common element in nuclear fusion is
- Velocities of sound measured in hydrogen and oxygen gas at a given temperature
- At the first minimum adjacent to the central maximum of a single-slit diffraction
Topics: Oscillations
(58)
Subject: Physics
(2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
- When ultraviolet rays are incident on metal plate, then photoelectric effect
- 1 a.m.u. is equivalent to
- The atomic number of the most common element in nuclear fusion is
- Velocities of sound measured in hydrogen and oxygen gas at a given temperature
- At the first minimum adjacent to the central maximum of a single-slit diffraction
Topics: Oscillations (58)
Subject: Physics (2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
18000+ students are using NEETLab to improve their score. What about you?
Solve Previous Year MCQs, Mock Tests, Topicwise Practice Tests, Identify Weak Topics, Formula Flash cards and much more is available in NEETLab Android App to improve your NEET score.
Share this page with your friends
Leave a Reply