| ⇦ |
| ⇨ |
Two simple harmonic motions of angular frequency 100 and 1000 rad s⁻¹ have the same displacement amplitude. The ratio of other maximum accelerations is:
Options
(a) 1 : 10
(b) 1 : 10²
(c) 1 : 10³
(d) 1 : 10⁴
Correct Answer:
1 : 10²
Explanation:
Maximum acceleration of a particle in the simple harmonic motion is directly proportional to the square of angular frequency i.e., a(max)= – w ² A
As A remains same, we can say
a₁ / a₂ = w₁² / w₂² = (100)² / (1000)² = 1 / 100
⇒ a₁ : a₂ = 1 : 10²
Related Questions: - The identical loops of copper and aluminium are moving with the same speed
- A ballet dancer, dancing on smooth floor, is spinning about a vertical axis
- An alternating voltage of 220 V, 50 Hz frequency is applied across a capacitor
- A heavy uniform chain lies on a horizontal top table.If the coefficient of friction
- Two planets at mean distances d₁ and d₂ from the sun have their frequencies n₁ and n₂
Topics: Oscillations
(58)
Subject: Physics
(2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
- The identical loops of copper and aluminium are moving with the same speed
- A ballet dancer, dancing on smooth floor, is spinning about a vertical axis
- An alternating voltage of 220 V, 50 Hz frequency is applied across a capacitor
- A heavy uniform chain lies on a horizontal top table.If the coefficient of friction
- Two planets at mean distances d₁ and d₂ from the sun have their frequencies n₁ and n₂
Topics: Oscillations (58)
Subject: Physics (2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
18000+ students are using NEETLab to improve their score. What about you?
Solve Previous Year MCQs, Mock Tests, Topicwise Practice Tests, Identify Weak Topics, Formula Flash cards and much more is available in NEETLab Android App to improve your NEET score.
Share this page with your friends

Leave a Reply