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**Two simple harmonic motions of angular frequency 100 and 1000 rad s⁻¹ have the same displacement amplitude. The ratio of other maximum accelerations is: **

### Options

(a) 1 : 10

(b) 1 : 10²

(c) 1 : 10³

(d) 1 : 10⁴

### Correct Answer:

1 : 10²

### Explanation:

Maximum acceleration of a particle in the simple harmonic motion is directly proportional to the square of angular frequency i.e., a(max)= – w ² A

As A remains same, we can say

a₁ / a₂ = w₁² / w₂² = (100)² / (1000)² = 1 / 100

⇒ a₁ : a₂ = 1 : 10²

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Topics: Oscillations
(58)

Subject: Physics
(2479)

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