| ⇦ | 
| ⇨ |
Two simple harmonic motions of angular frequency 100 and 1000 rad s⁻¹ have the same displacement amplitude. The ratio of other maximum accelerations is:
Options
(a) 1 : 10
(b) 1 : 10²
(c) 1 : 10³
(d) 1 : 10⁴
Correct Answer:
1 : 10²
Explanation:
Maximum acceleration of a particle in the simple harmonic motion is directly proportional to the square of angular frequency i.e., a(max)= – w ² A
As A remains same, we can say
a₁ / a₂ = w₁² / w₂² = (100)² / (1000)² = 1 / 100
⇒ a₁ : a₂ = 1 : 10²
Related Questions: - When temperature of an ideal gas is increased from 27⁰C to 227⁰C,
- If a body travels half the distance with velocity v1 and the next half with velocity v2
- A radioactive nucleus emits a beta particle. The parent and daughter nuclei are
- The rest mass of a body is m1. It moves with a velocity of 0.6c, then its relativistic
- A fluid is in streamline flow across a horizontal pipe of variable area of cross section
Topics: Oscillations
(58)
Subject: Physics
(2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
- When temperature of an ideal gas is increased from 27⁰C to 227⁰C,
- If a body travels half the distance with velocity v1 and the next half with velocity v2
- A radioactive nucleus emits a beta particle. The parent and daughter nuclei are
- The rest mass of a body is m1. It moves with a velocity of 0.6c, then its relativistic
- A fluid is in streamline flow across a horizontal pipe of variable area of cross section
Topics: Oscillations (58)
Subject: Physics (2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
18000+ students are using NEETLab to improve their score. What about you?
Solve Previous Year MCQs, Mock Tests, Topicwise Practice Tests, Identify Weak Topics, Formula Flash cards and much more is available in NEETLab Android App to improve your NEET score.
Share this page with your friends
Leave a Reply