| ⇦ | 
| ⇨ |
The resistance of a carbon resistor of colour code Red-Red Green Silver is (in kΩ)
Options
(a) 2200±5%
(b) 2200±10%
(c) 220±10%
(d) 220±5%
Correct Answer:
2200±10%
Explanation:
Given, Colour coding of resistance = Red, Red, Green, Silver
First band value = 2
Second band value = 2
Third band value = 10⁵
Fourth band value = ± 10%
Now, R = 22 × 10⁵ ± 10% Ω
R = 2200 ± 10% kΩ
Related Questions: - Curie temperature above which
- A body revolved around the sun 27 times faster than the earth. What is the ratio
- Two discs of moment of inertia I₁ and I₂ and angular speeds ?￢ﾂﾁ and ?￢ﾂﾂ are rotating
- One-fourth length of a spring of force constant K is cut away. The force constant
- A particle with charge q is moving along a circle of radius R with unoform speed v.
Topics: Current Electricity
(136)
Subject: Physics
(2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
- Curie temperature above which
- A body revolved around the sun 27 times faster than the earth. What is the ratio
- Two discs of moment of inertia I₁ and I₂ and angular speeds ?￢ﾂﾁ and ?￢ﾂﾂ are rotating
- One-fourth length of a spring of force constant K is cut away. The force constant
- A particle with charge q is moving along a circle of radius R with unoform speed v.
Topics: Current Electricity (136)
Subject: Physics (2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
18000+ students are using NEETLab to improve their score. What about you?
Solve Previous Year MCQs, Mock Tests, Topicwise Practice Tests, Identify Weak Topics, Formula Flash cards and much more is available in NEETLab Android App to improve your NEET score.
Share this page with your friends
Leave a Reply