| ⇦ | 
| ⇨ |
In an LCR circuit, capacitance is changed from C to 2C. For the resonant frequency to remain unchanged, the inductance should be changed from L to
Options
(a) 4 L
(b) 2 L
(c) L/2
(d) L/4
Correct Answer:
L/2
Explanation:
At resonance ω = 1 / √(LC)
Since ω is constant,
Therefore, LC = L’C’ = L’ × 2C
⇒ L’ = L / 2
Related Questions: - A solenoid 1.5 m long and 0.4 cm in diameter possesses 10 turns per cm length
- The resistance in the two arms of the meter bridge are 5Ω and RΩ, respectively
- A satellite in a circular orbit of radius R has a period of 4 hours. Another satellite
- A carnot’s engine operates with source at 127° C and sink at 27°C
- The second overtone of an open pipe is in resonance with the first overtone
Topics: Electromagnetic Induction
(76)
Subject: Physics
(2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
- A solenoid 1.5 m long and 0.4 cm in diameter possesses 10 turns per cm length
- The resistance in the two arms of the meter bridge are 5Ω and RΩ, respectively
- A satellite in a circular orbit of radius R has a period of 4 hours. Another satellite
- A carnot’s engine operates with source at 127° C and sink at 27°C
- The second overtone of an open pipe is in resonance with the first overtone
Topics: Electromagnetic Induction (76)
Subject: Physics (2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
18000+ students are using NEETLab to improve their score. What about you?
Solve Previous Year MCQs, Mock Tests, Topicwise Practice Tests, Identify Weak Topics, Formula Flash cards and much more is available in NEETLab Android App to improve your NEET score.
Share this page with your friends
Leave a Reply