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In an LCR circuit, capacitance is changed from C to 2C. For the resonant frequency to remain unchanged, the inductance should be changed from L to
Options
(a) 4 L
(b) 2 L
(c) L/2
(d) L/4
Correct Answer:
L/2
Explanation:
At resonance ω = 1 / √(LC)
Since ω is constant,
Therefore, LC = L’C’ = L’ × 2C
⇒ L’ = L / 2
Related Questions: - A block of mass M is attached to the lower end of a vertical spring
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Topics: Electromagnetic Induction
(76)
Subject: Physics
(2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
- A block of mass M is attached to the lower end of a vertical spring
- A thin and circular disc of mass M and radius R is rotating in a horizontal plane
- A parallel plate capacitor as a uniform electric field E in the space between the plates
- The point of suspension λ of a simple pendulum with normal time period T₁ is moving
- The height at which the weight of a body becomes 1/16 th, its weight
Topics: Electromagnetic Induction (76)
Subject: Physics (2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
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