| ⇦ | 
| ⇨ |
In an LCR circuit, capacitance is changed from C to 2C. For the resonant frequency to remain unchanged, the inductance should be changed from L to
Options
(a) 4 L
(b) 2 L
(c) L/2
(d) L/4
Correct Answer:
L/2
Explanation:
At resonance ω = 1 / √(LC)
Since ω is constant,
Therefore, LC = L’C’ = L’ × 2C
⇒ L’ = L / 2
Related Questions: - Ohm’s law valid
- In the Davisson and Germer experiment, the velocity of electrons emitted from the
- The kinetic energy needed to project a body of mass m from the surface of earth
- A magnet of length 10 cm and magnetic moment 1 A-m² is placed
- A deutron is bombarded on ₈O¹⁶ nucleus and α-particle is emitted. The product nucleus is
Topics: Electromagnetic Induction
(76)
Subject: Physics
(2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
- Ohm’s law valid
- In the Davisson and Germer experiment, the velocity of electrons emitted from the
- The kinetic energy needed to project a body of mass m from the surface of earth
- A magnet of length 10 cm and magnetic moment 1 A-m² is placed
- A deutron is bombarded on ₈O¹⁶ nucleus and α-particle is emitted. The product nucleus is
Topics: Electromagnetic Induction (76)
Subject: Physics (2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
18000+ students are using NEETLab to improve their score. What about you?
Solve Previous Year MCQs, Mock Tests, Topicwise Practice Tests, Identify Weak Topics, Formula Flash cards and much more is available in NEETLab Android App to improve your NEET score.
Share this page with your friends
Leave a Reply