| ⇦ | 
| ⇨ |
In an LCR circuit, capacitance is changed from C to 2C. For the resonant frequency to remain unchanged, the inductance should be changed from L to
Options
(a) 4 L
(b) 2 L
(c) L/2
(d) L/4
Correct Answer:
L/2
Explanation:
At resonance ω = 1 / √(LC)
Since ω is constant,
Therefore, LC = L’C’ = L’ × 2C
⇒ L’ = L / 2
Related Questions: - The particle executing simple harmonic motion has a kinetic energy K₀cos²ωt.
- A Si and a Ge diode has identical physical dimensions. The bandgap in Si is larger
- The ratio of the acceleration for a solid sphere(mass m and radius R)rolling down
- A car moving with a speed of 50 kmh⁻¹ can be stopped by brakes after at least 6 m
- An atom bomb works on the principle of
Topics: Electromagnetic Induction
(76)
Subject: Physics
(2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
- The particle executing simple harmonic motion has a kinetic energy K₀cos²ωt.
- A Si and a Ge diode has identical physical dimensions. The bandgap in Si is larger
- The ratio of the acceleration for a solid sphere(mass m and radius R)rolling down
- A car moving with a speed of 50 kmh⁻¹ can be stopped by brakes after at least 6 m
- An atom bomb works on the principle of
Topics: Electromagnetic Induction (76)
Subject: Physics (2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
18000+ students are using NEETLab to improve their score. What about you?
Solve Previous Year MCQs, Mock Tests, Topicwise Practice Tests, Identify Weak Topics, Formula Flash cards and much more is available in NEETLab Android App to improve your NEET score.
Share this page with your friends
Leave a Reply