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The ratio of radii of planets A and B is K₁ and ratio of accelerations due to gravity on them is K₂. The ratio of escape velocities from them will be
Options
(a) K₁K₂
(b) √K₁K₂
(c) √K₁/K₂
(d) √K₂/K₁
Correct Answer:
√K₁K₂
Explanation:
Escape velocity Ve=(√2Rg)
The radii of two planets R₁/R₂=K₁
The acceleration due to gravity of two planets g₁/g₂=K₂
The escape velocity of two planets v₁/v₂=?
v₁/v₂=(√2R₁g₁/2R₂g₂)
=(√R₁/R₂.g₁/g₂)
=(√K₁K₂ )
Related Questions: - A particle moves from position r₁ = 3i + 2j -6k to position r₂ = 14i + 13 j+ 9 k
- One-fourth length of a spring of force constant K is cut away. The force constant
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Topics: Gravitation
(63)
Subject: Physics
(2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
- A particle moves from position r₁ = 3i + 2j -6k to position r₂ = 14i + 13 j+ 9 k
- One-fourth length of a spring of force constant K is cut away. The force constant
- Two bulbs when connected in parallel to a source take 60W each, the power consumed,
- Two identical capacitors are first connected in series and then in parallel.
- In which case positive work has to be done in seperating them?
Topics: Gravitation (63)
Subject: Physics (2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
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