| ⇦ |
| ⇨ |
A proton is projected with a speed of 3×10⁶ m/s horizontally from east to west. An uniform magnetic field of strength 2×10⁻³ T exist in the vertically upward direction. What would be the acceleration of proton?
Options
(a) 11.6×10¹¹ m/ s²
(b) 17.4×10¹¹ m/ s
(c) 5.8×10¹¹ m/ s²
(d) 2.9×10¹¹ m/ s²
Correct Answer:
5.8×10¹¹ m/ s²
Explanation:
No explanation available. Be the first to write the explanation for this question by commenting below.
Related Questions: - The intensity at the maximum in a Young’s double slit experiment is I₀.
- The escape velocity from the earth is Ve. The escape velocity from a planet
- The bandgap in Germanium and silicon, in eV, are respectively
- A wire of one metre length carries a constant current. The wire is bent to form
- A block of mass m is moving on a wedge with the acceleration aᵒ
Topics: Magnetic Effects of Current and Magnetism
(167)
Subject: Physics
(2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
- The intensity at the maximum in a Young’s double slit experiment is I₀.
- The escape velocity from the earth is Ve. The escape velocity from a planet
- The bandgap in Germanium and silicon, in eV, are respectively
- A wire of one metre length carries a constant current. The wire is bent to form
- A block of mass m is moving on a wedge with the acceleration aᵒ
Topics: Magnetic Effects of Current and Magnetism (167)
Subject: Physics (2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
18000+ students are using NEETLab to improve their score. What about you?
Solve Previous Year MCQs, Mock Tests, Topicwise Practice Tests, Identify Weak Topics, Formula Flash cards and much more is available in NEETLab Android App to improve your NEET score.
Share this page with your friends

Leave a Reply