| ⇦ | 
| ⇨ |
A proton is projected with a speed of 3×10⁶ m/s horizontally from east to west. An uniform magnetic field of strength 2×10⁻³ T exist in the vertically upward direction. What would be the acceleration of proton?
Options
(a) 11.6×10¹¹ m/ s²
(b) 17.4×10¹¹ m/ s
(c) 5.8×10¹¹ m/ s²
(d) 2.9×10¹¹ m/ s²
Correct Answer:
5.8×10¹¹ m/ s²
Explanation:
No explanation available. Be the first to write the explanation for this question by commenting below.
Related Questions: - Two bulbs 60 W and 100 W designed for voltage 220 V are connected in series
- A dip needle vibrates in a vertical plane perpendicular to magnetic meridian. The time
- Calculate the charge on equivalent capacitance of the conbination shown in figure
- If an electron and a positron annihilate, the energy released is
- A piece of marble is projected from the earth’s surface with velocity of 50 m/s
Topics: Magnetic Effects of Current and Magnetism
(167)
Subject: Physics
(2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
- Two bulbs 60 W and 100 W designed for voltage 220 V are connected in series
- A dip needle vibrates in a vertical plane perpendicular to magnetic meridian. The time
- Calculate the charge on equivalent capacitance of the conbination shown in figure
- If an electron and a positron annihilate, the energy released is
- A piece of marble is projected from the earth’s surface with velocity of 50 m/s
Topics: Magnetic Effects of Current and Magnetism (167)
Subject: Physics (2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
18000+ students are using NEETLab to improve their score. What about you?
Solve Previous Year MCQs, Mock Tests, Topicwise Practice Tests, Identify Weak Topics, Formula Flash cards and much more is available in NEETLab Android App to improve your NEET score.
Share this page with your friends
Leave a Reply