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Two planets at mean distances d₁ and d₂ from the sun have their frequencies n₁ and n₂ respectively. Then
Options
(a) n₁²d₁²=n₂²d₂²
(b) n₁²d₁³=n₂²d₂³
(c) n₁d₁²=n₂d₂²
(d) n₁²d₁=n₂²d₂
Correct Answer:
n₁²d₁³=n₂²d₂³
Explanation:
Apply Kepler’s third law, T²∞R³
T²/R³=constant
Given: T=1/n and R=d
T²/R³=1/n².1/d³=constant
n²d³=constant
For the two planets,n₁²d₁³=n₂²d₂³
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Topics: Gravitation
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Subject: Physics
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Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
- A particle moves along the x-axis from x=0 to x=5 m under the influence of a force
- A light of wavelength 5000Å falls on a sensitive plate with photoelectric work
- Two strings A and B, made of same material are stretched by same tension
- Three identical spheres, each of mass 3 kg are placed touching each other
- If a vector 2i+3j+8k is perpendicular to the vector 4j-4i+αk, then value of α is
Topics: Gravitation (63)
Subject: Physics (2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
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