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The ratio of amplitude of magnetic field to the amplitude of electric field for an electromagnetic wave propagating in vacuum is equal to:
Options
(a) The speed of light in vacuum
(b) reciprocal of speed of light in vacuum
(c) the ratio of magnetic permeability to the electric susceptibility of vacuum
(d) unity
Correct Answer:
reciprocal of speed of light in vacuum
Explanation:
The average energy stored in the electric field Uᴇ = (1/2) ε₀E²
The average energy stroed in the magnetic field Uв = (1/2) . (B² /μ₀),
According to conservation of energy Ue = Ub
ε₀μ₀ = B² / E²
B / E = √(ε₀μ₀) = 1/C
Related Questions: - When two displacements represented by y₁=a sin(?t) are superimposed the motion is
- A particle moving in a straight line with uniform acceleration is observed
- When 10¹⁹elecrons are removed from a neutral metal plate through some process,
- A stone thrown into still water, creates a circular wave pattern moving radially
- An electric dipole of moment ‘p’ is placed in an elecatric field of intensity ‘E’
Topics: Electromagnetic Waves
(28)
Subject: Physics
(2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
- When two displacements represented by y₁=a sin(?t) are superimposed the motion is
- A particle moving in a straight line with uniform acceleration is observed
- When 10¹⁹elecrons are removed from a neutral metal plate through some process,
- A stone thrown into still water, creates a circular wave pattern moving radially
- An electric dipole of moment ‘p’ is placed in an elecatric field of intensity ‘E’
Topics: Electromagnetic Waves (28)
Subject: Physics (2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
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