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The ratio of amplitude of magnetic field to the amplitude of electric field for an electromagnetic wave propagating in vacuum is equal to:
Options
(a) The speed of light in vacuum
(b) reciprocal of speed of light in vacuum
(c) the ratio of magnetic permeability to the electric susceptibility of vacuum
(d) unity
Correct Answer:
reciprocal of speed of light in vacuum
Explanation:
The average energy stored in the electric field Uᴇ = (1/2) ε₀E²
The average energy stroed in the magnetic field Uв = (1/2) . (B² /μ₀),
According to conservation of energy Ue = Ub
ε₀μ₀ = B² / E²
B / E = √(ε₀μ₀) = 1/C
Related Questions: - When light of wavelength 300 nm falls on a photoelectric emitter,
- Three particles A,B and C are thrown from the top of a tower with the same speed.
- A body of mass 3 kg acted upon by a constant force is displaced by S meter
- Two tuning forks are sounded together and produce 2 beats per second.
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Topics: Electromagnetic Waves
(28)
Subject: Physics
(2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
- When light of wavelength 300 nm falls on a photoelectric emitter,
- Three particles A,B and C are thrown from the top of a tower with the same speed.
- A body of mass 3 kg acted upon by a constant force is displaced by S meter
- Two tuning forks are sounded together and produce 2 beats per second.
- An oscillator circuit consists of an inductance of 0. mH and a capacitor of 20 μF.
Topics: Electromagnetic Waves (28)
Subject: Physics (2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
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