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A radioactive nucleus of mass M emits a photon of frequency v and the nucleus recoils. The recoil energy will be
Options
(a) Mc² – hv
(b) h²v² / 2Mc²
(c) zero
(d) hv
Correct Answer:
h²v² / 2Mc²
Explanation:
Momentum Mu = E/c = hv / c
Recoil energy
1/2 Mu² = 1/2 . M²u² / M = 1/2M (hv/c)²
= h²v² / 2Mc²
Related Questions: - Masses of three wires of copper are in the ratio of 1:3:5 and their lengths
- The current gain of a transistor in common base configuration is 0.96.
- A thin rod of length L and mass M is bent at its midpoint into two halves
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Topics: Radioactivity
(83)
Subject: Physics
(2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
- Masses of three wires of copper are in the ratio of 1:3:5 and their lengths
- The current gain of a transistor in common base configuration is 0.96.
- A thin rod of length L and mass M is bent at its midpoint into two halves
- When you make ice cubes, the entropy of water
- 3 persons are initially at the 3 corners of an equilateral triangle
Topics: Radioactivity (83)
Subject: Physics (2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
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