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A radioactive nucleus of mass M emits a photon of frequency v and the nucleus recoils. The recoil energy will be
Options
(a) Mc² – hv
(b) h²v² / 2Mc²
(c) zero
(d) hv
Correct Answer:
h²v² / 2Mc²
Explanation:
Momentum Mu = E/c = hv / c
Recoil energy
1/2 Mu² = 1/2 . M²u² / M = 1/2M (hv/c)²
= h²v² / 2Mc²
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Topics: Radioactivity
(83)
Subject: Physics
(2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
- A disc of moment of inertia (9.8/π²) kg m² is rotating at 600 rpm. If the frequency
- Which of the following transitions in hydrogen atoms emit photons of highest frequency?
- RMS velocity of gas is proportional to
- If voltage across a bulb rated 220 volt-100 Watt drops by 2.5% of its rated value
- A body travels 200 cm in the first two seconds and 220 cm in the next 4 secs
Topics: Radioactivity (83)
Subject: Physics (2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
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