⇦ | ⇨ |
A radioactive nucleus of mass M emits a photon of frequency v and the nucleus recoils. The recoil energy will be
Options
(a) Mc² – hv
(b) h²v² / 2Mc²
(c) zero
(d) hv
Correct Answer:
h²v² / 2Mc²
Explanation:
Momentum Mu = E/c = hv / c
Recoil energy
1/2 Mu² = 1/2 . M²u² / M = 1/2M (hv/c)²
= h²v² / 2Mc²
Related Questions: - In Young’s double slit experiment, the ratio of maximum and minimum intensities
- A 70 kg man stands in contact against the inner wall of a hollow cylindrical drum
- If r be the distance of a point on the axis of a magnetic dipole from its centre
- Time period of the rotation of the earth about its own axis is 24 hour
- The energy of groundstate (n=1) of hydrogen level is -13.6 eV. The ionistation
Topics: Radioactivity
(83)
Subject: Physics
(2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
- In Young’s double slit experiment, the ratio of maximum and minimum intensities
- A 70 kg man stands in contact against the inner wall of a hollow cylindrical drum
- If r be the distance of a point on the axis of a magnetic dipole from its centre
- Time period of the rotation of the earth about its own axis is 24 hour
- The energy of groundstate (n=1) of hydrogen level is -13.6 eV. The ionistation
Topics: Radioactivity (83)
Subject: Physics (2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
18000+ students are using NEETLab to improve their score. What about you?
Solve Previous Year MCQs, Mock Tests, Topicwise Practice Tests, Identify Weak Topics, Formula Flash cards and much more is available in NEETLab Android App to improve your NEET score.
Share this page with your friends
Leave a Reply