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A radioactive nucleus of mass M emits a photon of frequency v and the nucleus recoils. The recoil energy will be
Options
(a) Mc² – hv
(b) h²v² / 2Mc²
(c) zero
(d) hv
Correct Answer:
h²v² / 2Mc²
Explanation:
Momentum Mu = E/c = hv / c
Recoil energy
1/2 Mu² = 1/2 . M²u² / M = 1/2M (hv/c)²
= h²v² / 2Mc²
Related Questions: - Electrons with energy 80 keV are incident on the tungsten target of an X-ray tube.
- A step-up transformer operates on a 230 V line and supplies a current of 2 A.
- A thin and circular disc of mass M and radius R is rotating in a horizontal plane
- Identify the wrong statement with reference to solar cell
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Topics: Radioactivity
(83)
Subject: Physics
(2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
- Electrons with energy 80 keV are incident on the tungsten target of an X-ray tube.
- A step-up transformer operates on a 230 V line and supplies a current of 2 A.
- A thin and circular disc of mass M and radius R is rotating in a horizontal plane
- Identify the wrong statement with reference to solar cell
- Pure Si at 300 k has equal electrons (nₑ) and hole (nh) concentrations
Topics: Radioactivity (83)
Subject: Physics (2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
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