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A radioactive nucleus of mass M emits a photon of frequency v and the nucleus recoils. The recoil energy will be
Options
(a) Mc² – hv
(b) h²v² / 2Mc²
(c) zero
(d) hv
Correct Answer:
h²v² / 2Mc²
Explanation:
Momentum Mu = E/c = hv / c
Recoil energy
1/2 Mu² = 1/2 . M²u² / M = 1/2M (hv/c)²
= h²v² / 2Mc²
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Topics: Radioactivity
(83)
Subject: Physics
(2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
- A car accelerates from rest at constant rate for first 10s and covers a distance x.
- Two cars A and B moving with same speed of 45 km/hr along same direction.
- A spring of spring constant 5 x 10³ Nm⁻¹ is streched intially by 5 cm from
- A wire mesh consisting of very small squares is viewed at a distance
- If energy(E), velocity(V) and time(T) are chosen as fundamental quantities,
Topics: Radioactivity (83)
Subject: Physics (2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
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