| ⇦ | 
| ⇨ |
A radioactive nucleus of mass M emits a photon of frequency v and the nucleus recoils. The recoil energy will be
Options
(a) Mc² – hv
(b) h²v² / 2Mc²
(c) zero
(d) hv
Correct Answer:
h²v² / 2Mc²
Explanation:
Momentum Mu = E/c = hv / c
Recoil energy
1/2 Mu² = 1/2 . M²u² / M = 1/2M (hv/c)²
= h²v² / 2Mc²
Related Questions: - If 10000 V is applied across an X-ray tube, what will be the ratio of de-Broglie
- A road of width 20 m forms an arc of radius 15 m,its outer edge is 2m higher than
- A particle of mass 1.96×10⁻¹⁵ kg is kept in equilibrium between two horizontal metal
- An alternating voltage e=200s in100t is applied to a series combination
- Fission of nuclei is possible because the binding energy per nucleon in them
Topics: Radioactivity
(83)
Subject: Physics
(2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
- If 10000 V is applied across an X-ray tube, what will be the ratio of de-Broglie
- A road of width 20 m forms an arc of radius 15 m,its outer edge is 2m higher than
- A particle of mass 1.96×10⁻¹⁵ kg is kept in equilibrium between two horizontal metal
- An alternating voltage e=200s in100t is applied to a series combination
- Fission of nuclei is possible because the binding energy per nucleon in them
Topics: Radioactivity (83)
Subject: Physics (2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
18000+ students are using NEETLab to improve their score. What about you?
Solve Previous Year MCQs, Mock Tests, Topicwise Practice Tests, Identify Weak Topics, Formula Flash cards and much more is available in NEETLab Android App to improve your NEET score.
Share this page with your friends
Leave a Reply