| ⇦ |
| ⇨ |
The radioactivity of a certain material drops to 1/16 of the initial value in 2 hours. The half-life of this radio nuclide is
Options
(a) 10 min
(b) 20 min
(c) 30 min
(d) 40 min
Correct Answer:
30 min
Explanation:
In 4 × T₁/₂, N = (N₀ / 2) × (1 / 2) × (1 / 2) × (1 / 2)
= N₀ / 16 4 × T₁/₂ = 2 hrs.
⇒ T₁/₂ = 30 min
Related Questions: - Cohesive force is experienced between
- In common base mode of a transistor, the collector current is 5.488 mA
- The interferance pattern is obtained with two coherent light sources of intensity
- An avarage induced e.m.f. of 1 V appears in a coil when the current in it is changed
- The threshold frequency for a metallic surface corresponds to an energy of 6.2 eV,
Topics: Radioactivity
(83)
Subject: Physics
(2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
- Cohesive force is experienced between
- In common base mode of a transistor, the collector current is 5.488 mA
- The interferance pattern is obtained with two coherent light sources of intensity
- An avarage induced e.m.f. of 1 V appears in a coil when the current in it is changed
- The threshold frequency for a metallic surface corresponds to an energy of 6.2 eV,
Topics: Radioactivity (83)
Subject: Physics (2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
18000+ students are using NEETLab to improve their score. What about you?
Solve Previous Year MCQs, Mock Tests, Topicwise Practice Tests, Identify Weak Topics, Formula Flash cards and much more is available in NEETLab Android App to improve your NEET score.
Share this page with your friends

Leave a Reply