| ⇦ |
| ⇨ |
A conductor of length 5 cm is moved parallel to itself with a speed of 2 m/s, perpendicular to a uniform magnetic field of 10⁻³ Wb/m². The induced emf generated is
Options
(a) 2×10⁻³ V
(b) 1×10⁻³ V
(c) 1×10⁻⁴ V
(d) 2×10⁻⁴ V
Correct Answer:
1×10⁻⁴ V
Explanation:
No explanation available. Be the first to write the explanation for this question by commenting below.
Related Questions: - The two ends of a rod of length L and a uniform cross-sectional area
- Function of a rectifier is
- During an adiabatic process, the pressure of a gas is found to be proportional
- Light propagates rectilinearly because of its
- The drift speed of electrons in copper wire of diameter and length l is v.
Topics: Electromagnetic Induction
(76)
Subject: Physics
(2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
- The two ends of a rod of length L and a uniform cross-sectional area
- Function of a rectifier is
- During an adiabatic process, the pressure of a gas is found to be proportional
- Light propagates rectilinearly because of its
- The drift speed of electrons in copper wire of diameter and length l is v.
Topics: Electromagnetic Induction (76)
Subject: Physics (2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
18000+ students are using NEETLab to improve their score. What about you?
Solve Previous Year MCQs, Mock Tests, Topicwise Practice Tests, Identify Weak Topics, Formula Flash cards and much more is available in NEETLab Android App to improve your NEET score.
Share this page with your friends

Leave a Reply