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The power obtained in a reactor using U²³⁵ disintegration is 1000 kW. The mass decay of U²³⁵ per hour is
Options
(a) 10 microgram
(b) 20 microgram
(c) 40 microgram
(d) 1 microgram
Correct Answer:
40 microgram
Explanation:
E = mc² m = E / c² so, mass decay per second.
dm/ dt = 1/c² . dE/ dt = 1/c² (Power in watt)
= 1 / (3 x 10⁸)² x 1000 x 10³
and mass decay per hour = dm/ dt x 60 x 60
= 1 / (3 x 10⁸)² x 10⁶ x 3600 = 4 x 10⁻⁸ kg = 40 microgram
Related Questions: - Two conducting spheres of radii 5 cm and 10 cm are given a charge of 15 μC each.
- A thin equiconvex lens of refractive index 3/2 and radius of curvature 30 cm
- The radius of orbit of a planet is two times that of the earth. The time period
- 34 gram of water at 30⁰C is poured into a calorimeter at 15⁰C.
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Topics: Atoms and Nuclei
(136)
Subject: Physics
(2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
- Two conducting spheres of radii 5 cm and 10 cm are given a charge of 15 μC each.
- A thin equiconvex lens of refractive index 3/2 and radius of curvature 30 cm
- The radius of orbit of a planet is two times that of the earth. The time period
- 34 gram of water at 30⁰C is poured into a calorimeter at 15⁰C.
- The value of n so that vectors 2i+3j-2k, 5i+nj+k and -i+2j+3k may be coplanar,will be
Topics: Atoms and Nuclei (136)
Subject: Physics (2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
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