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The power obtained in a reactor using U²³⁵ disintegration is 1000 kW. The mass decay of U²³⁵ per hour is
Options
(a) 10 microgram
(b) 20 microgram
(c) 40 microgram
(d) 1 microgram
Correct Answer:
40 microgram
Explanation:
E = mc² m = E / c² so, mass decay per second.
dm/ dt = 1/c² . dE/ dt = 1/c² (Power in watt)
= 1 / (3 x 10⁸)² x 1000 x 10³
and mass decay per hour = dm/ dt x 60 x 60
= 1 / (3 x 10⁸)² x 10⁶ x 3600 = 4 x 10⁻⁸ kg = 40 microgram
Related Questions: - A p-n-p transistor is used in common emitter mode in an amplifier circuit.
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Topics: Atoms and Nuclei
(136)
Subject: Physics
(2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
- A p-n-p transistor is used in common emitter mode in an amplifier circuit.
- When a beam of light is used to determine the position of an object,
- The work function for aluminium is 4.125 eV. The cutoff wavelength for photoelectric
- A 6 volt battery is connected to the terminals of a three metre long wire of uniform
- For transistor action (1) Base, emitter and collector regions should have similar size
Topics: Atoms and Nuclei (136)
Subject: Physics (2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
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