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The power obtained in a reactor using U²³⁵ disintegration is 1000 kW. The mass decay of U²³⁵ per hour is
Options
(a) 10 microgram
(b) 20 microgram
(c) 40 microgram
(d) 1 microgram
Correct Answer:
40 microgram
Explanation:
E = mc² m = E / c² so, mass decay per second.
dm/ dt = 1/c² . dE/ dt = 1/c² (Power in watt)
= 1 / (3 x 10⁸)² x 1000 x 10³
and mass decay per hour = dm/ dt x 60 x 60
= 1 / (3 x 10⁸)² x 10⁶ x 3600 = 4 x 10⁻⁸ kg = 40 microgram
Related Questions: - An automobile engine develops 100 kW when rotating at a speed of 1800 rev/min
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Topics: Atoms and Nuclei
(136)
Subject: Physics
(2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
- An automobile engine develops 100 kW when rotating at a speed of 1800 rev/min
- A parallel beam of fast moving electrons is incident normally on a narrow slit.
- The workdone in turning a magnet of magnetic moment M by an angle of 90⁰ from the magnetic
- Young’s modulus of perfectly rigid body material is
- The electric field in a certain region is acting radially outward and is given by E=Ar.
Topics: Atoms and Nuclei (136)
Subject: Physics (2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
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