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For a satellite moving in an orbit around the earth, the ratio of kinetic energy to potential energy is
Options
(a) (1/2)
(b) 1/√2
(c) 2
(d) √2
Correct Answer:
(1/2)
Explanation:
-GMm/R² + mω²R = 0
GMm/R² = mω²R
Kinetic Energy = 1/2Iω²
KE= 1/2mR²ω² = GMm/2R
Potential energy = -GMm/R
Therefore, Kinetic energy = |Potential energy|/2
Kinetic energy/|Potential energy| = 1/2.
Related Questions: - A particle under the action of a constant force moves from rest upto 20 seconds
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Topics: Gravitation
(63)
Subject: Physics
(2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
- A particle under the action of a constant force moves from rest upto 20 seconds
- IF A⃗ and B⃗ are two vectors and θ is the angle between them
- Two balls are dropped from same height at 1 second interval of time.
- The bandgap in Germanium and silicon, in eV, are respectively
- Three cells, each of e.m.f 1.5 V and internal resistance 1 ohm are connected in parallel
Topics: Gravitation (63)
Subject: Physics (2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
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