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For a satellite moving in an orbit around the earth, the ratio of kinetic energy to potential energy is
Options
(a) (1/2)
(b) 1/√2
(c) 2
(d) √2
Correct Answer:
(1/2)
Explanation:
-GMm/R² + mω²R = 0
GMm/R² = mω²R
Kinetic Energy = 1/2Iω²
KE= 1/2mR²ω² = GMm/2R
Potential energy = -GMm/R
Therefore, Kinetic energy = |Potential energy|/2
Kinetic energy/|Potential energy| = 1/2.
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Topics: Gravitation
(63)
Subject: Physics
(2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
- A beam of light of wavelength 600 nm from a distant source falls
- When radiation is incident on a photoelectron emitter,
- If the length of a stretched string is shortened by 4% and the tension is increased
- If light emitted from sodium bulb is passed through sodium vapour,
- A charged particle with a velocity 2×10³ ms⁻¹ passes undeflected through electric field
Topics: Gravitation (63)
Subject: Physics (2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
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