| ⇦ |
| ⇨ |
For a satellite moving in an orbit around the earth, the ratio of kinetic energy to potential energy is
Options
(a) (1/2)
(b) 1/√2
(c) 2
(d) √2
Correct Answer:
(1/2)
Explanation:
-GMm/R² + mω²R = 0
GMm/R² = mω²R
Kinetic Energy = 1/2Iω²
KE= 1/2mR²ω² = GMm/2R
Potential energy = -GMm/R
Therefore, Kinetic energy = |Potential energy|/2
Kinetic energy/|Potential energy| = 1/2.
Related Questions: - A proton carrying 1 MeV kinetic energy is moving in a circular path of radius
- A common emitter amplifier has a voltage gain of 50, an input impedance of 100Ω
- Calculate the charge on equivalent capacitance of the conbination shown in figure
- The current in the windings of a toroid is 2.0 A. There are 400 turns
- The force of repulsion between two electrons at a certain distance is F.
Topics: Gravitation
(63)
Subject: Physics
(2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
- A proton carrying 1 MeV kinetic energy is moving in a circular path of radius
- A common emitter amplifier has a voltage gain of 50, an input impedance of 100Ω
- Calculate the charge on equivalent capacitance of the conbination shown in figure
- The current in the windings of a toroid is 2.0 A. There are 400 turns
- The force of repulsion between two electrons at a certain distance is F.
Topics: Gravitation (63)
Subject: Physics (2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
18000+ students are using NEETLab to improve their score. What about you?
Solve Previous Year MCQs, Mock Tests, Topicwise Practice Tests, Identify Weak Topics, Formula Flash cards and much more is available in NEETLab Android App to improve your NEET score.
Share this page with your friends

Leave a Reply