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For a satellite moving in an orbit around the earth, the ratio of kinetic energy to potential energy is
Options
(a) (1/2)
(b) 1/√2
(c) 2
(d) √2
Correct Answer:
(1/2)
Explanation:
-GMm/R² + mω²R = 0
GMm/R² = mω²R
Kinetic Energy = 1/2Iω²
KE= 1/2mR²ω² = GMm/2R
Potential energy = -GMm/R
Therefore, Kinetic energy = |Potential energy|/2
Kinetic energy/|Potential energy| = 1/2.
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Topics: Gravitation
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Subject: Physics
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Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
- A transformer having efficiency of 90% is working on 200 V and 3kW power supply
- A magnet of length 10 cm and magnetic moment 1 A-m² is placed
- A double slit experiment is performed with light of wavelength 500 nm. A thin film
- A neutron is moving with a velocity u.It collides head on and elastically with an atom
- An aeroplane flies 400m due to North and then 300m due to south and then flies
Topics: Gravitation (63)
Subject: Physics (2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
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