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The potential energy of a simple harmonic oscillator when the particle is half way to its end point is (where E is the total energy)
Options
(a) E/8
(b) E/4
(c) E/2
(d) 2E/3
Correct Answer:
E/4
Explanation:
P.E. = (1/2) mω²y² ⇒ At y = a/2 ⇒ (1/2) (mω²a²/4)
Total energy (E) = P.E. at extreme position = (1/2) mω²a²
P.E. = (1/4).[(1/2) mω²a²] = E/4
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Topics: Oscillations
(58)
Subject: Physics
(2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
- Masses of three wires of copper are in the ratio of 1:3:5 and their lengths
- In the experiment for determination of velocity of sound in air,
- The velocity of radio-waves is 3×10⁵ km/s. The frequency corresponding to wavelength
- A stone tied to the end of a string of 1 m long is whirled in a horizontal circle
- A parallel plate capacitor with air between the plates has a capacitance of 9 pF.
Topics: Oscillations (58)
Subject: Physics (2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
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