| ⇦ |
| ⇨ |
The potential energy of a simple harmonic oscillator when the particle is half way to its end point is (where E is the total energy)
Options
(a) E/8
(b) E/4
(c) E/2
(d) 2E/3
Correct Answer:
E/4
Explanation:
P.E. = (1/2) mω²y² ⇒ At y = a/2 ⇒ (1/2) (mω²a²/4)
Total energy (E) = P.E. at extreme position = (1/2) mω²a²
P.E. = (1/4).[(1/2) mω²a²] = E/4
Related Questions: - A radioactive nucleus emits a beta particle. The parent and daughter nuclei are
- Monochromatic light of wavelength 667 nm is produced by a helium neon laser
- The wavelength of the matter wave is independent of
- The distance travelled by a particle starting from rest and moving with an acceleration
- In a semiconductor
Topics: Oscillations
(58)
Subject: Physics
(2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
- A radioactive nucleus emits a beta particle. The parent and daughter nuclei are
- Monochromatic light of wavelength 667 nm is produced by a helium neon laser
- The wavelength of the matter wave is independent of
- The distance travelled by a particle starting from rest and moving with an acceleration
- In a semiconductor
Topics: Oscillations (58)
Subject: Physics (2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
18000+ students are using NEETLab to improve their score. What about you?
Solve Previous Year MCQs, Mock Tests, Topicwise Practice Tests, Identify Weak Topics, Formula Flash cards and much more is available in NEETLab Android App to improve your NEET score.
Share this page with your friends

Leave a Reply