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The potential energy of a simple harmonic oscillator when the particle is half way to its end point is (where E is the total energy)
Options
(a) E/8
(b) E/4
(c) E/2
(d) 2E/3
Correct Answer:
E/4
Explanation:
P.E. = (1/2) mω²y² ⇒ At y = a/2 ⇒ (1/2) (mω²a²/4)
Total energy (E) = P.E. at extreme position = (1/2) mω²a²
P.E. = (1/4).[(1/2) mω²a²] = E/4
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Topics: Oscillations
(58)
Subject: Physics
(2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
- Two bodies of mass 1 kg and 3 kg have positive vectors i + 2j + k and -3i -2j + k
- If the rise in height of capillary of two tubes is 6.6 cm and 2.2 cm
- A particle free to move along X-axis has potential energy given as U(X) =k(1-e⁻ˣ²)
- Ist law of thermadynamics is based on
- A wire is stretched under a force. If the wire suddenly snaps the temperature
Topics: Oscillations (58)
Subject: Physics (2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
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