⇦ | ⇨ |
A particle executing simple harmonic motion of amplitude 5 cm has maximum speed of 31.4 cm/s. The frequency of its oscillation is
Options
(a) 4 Hz
(b) 3 Hz
(c) 2 Hz
(d) 1 Hz
Correct Answer:
1 Hz
Explanation:
a = 5 cm, vₘₐₓ = 31.4 cm/s
vₘₐₓ = ωa ⇒ 31.4 = 2πʋ × 5
⇒ 31.4 = 10 × 31.4 × ʋ
⇒ ʋ = 1 Hz
Related Questions: - A circular road of radius 1000m has banking angle 45°.The maximum safe speed of a car
- Dependence of intensity of gravitational field (E) of earth with distance(r)
- The interferance pattern is obtained with two coherent light sources of intensity
- A bomb of mass 16 kg at rest explodes into two pieces of masses of 4 kg and 12 kg.
- A p-n photodiode is made of a material with a band gap of 2.0 eV
Topics: Oscillations
(58)
Subject: Physics
(2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
- A circular road of radius 1000m has banking angle 45°.The maximum safe speed of a car
- Dependence of intensity of gravitational field (E) of earth with distance(r)
- The interferance pattern is obtained with two coherent light sources of intensity
- A bomb of mass 16 kg at rest explodes into two pieces of masses of 4 kg and 12 kg.
- A p-n photodiode is made of a material with a band gap of 2.0 eV
Topics: Oscillations (58)
Subject: Physics (2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
18000+ students are using NEETLab to improve their score. What about you?
Solve Previous Year MCQs, Mock Tests, Topicwise Practice Tests, Identify Weak Topics, Formula Flash cards and much more is available in NEETLab Android App to improve your NEET score.
Share this page with your friends
Leave a Reply