| ⇦ | 
| ⇨ |
A particle executing simple harmonic motion of amplitude 5 cm has maximum speed of 31.4 cm/s. The frequency of its oscillation is
Options
(a) 4 Hz
(b) 3 Hz
(c) 2 Hz
(d) 1 Hz
Correct Answer:
1 Hz
Explanation:
a = 5 cm, vₘₐₓ = 31.4 cm/s
vₘₐₓ = ωa ⇒ 31.4 = 2πʋ × 5
⇒ 31.4 = 10 × 31.4 × ʋ
⇒ ʋ = 1 Hz
Related Questions: - Let A = i Acosθ +j B sinθ be any vector.Another vector B which is normal to A is
- A step-down transformer has 50 turns on secondary and 1000 turns on primary winding.
- In radioactive element, β-rays are emitted from
- The radius of a planet is twice the radius of earth. Both have almost
- A 220 volt and 1000 watt bulb is connected across a 110 volt mains supply.
Topics: Oscillations
(58)
Subject: Physics
(2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
- Let A = i Acosθ +j B sinθ be any vector.Another vector B which is normal to A is
- A step-down transformer has 50 turns on secondary and 1000 turns on primary winding.
- In radioactive element, β-rays are emitted from
- The radius of a planet is twice the radius of earth. Both have almost
- A 220 volt and 1000 watt bulb is connected across a 110 volt mains supply.
Topics: Oscillations (58)
Subject: Physics (2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
18000+ students are using NEETLab to improve their score. What about you?
Solve Previous Year MCQs, Mock Tests, Topicwise Practice Tests, Identify Weak Topics, Formula Flash cards and much more is available in NEETLab Android App to improve your NEET score.
Share this page with your friends
Leave a Reply