| ⇦ | 
| ⇨ |
A particle executing simple harmonic motion of amplitude 5 cm has maximum speed of 31.4 cm/s. The frequency of its oscillation is
Options
(a) 4 Hz
(b) 3 Hz
(c) 2 Hz
(d) 1 Hz
Correct Answer:
1 Hz
Explanation:
a = 5 cm, vₘₐₓ = 31.4 cm/s
vₘₐₓ = ωa ⇒ 31.4 = 2πʋ × 5
⇒ 31.4 = 10 × 31.4 × ʋ
⇒ ʋ = 1 Hz
Related Questions: - An electron is moving in a circular path under the influence of a transverse magnetic
- Function of a rectifier is
- A spherical shell of radius 10cm is carrying a charge q. If the electric potential
- An object placed at 20 cm in front of a concave mirror produces three times
- If an A.C. mains supply is given to be 220 V, what would be the average e.m.f.
Topics: Oscillations
(58)
Subject: Physics
(2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
- An electron is moving in a circular path under the influence of a transverse magnetic
- Function of a rectifier is
- A spherical shell of radius 10cm is carrying a charge q. If the electric potential
- An object placed at 20 cm in front of a concave mirror produces three times
- If an A.C. mains supply is given to be 220 V, what would be the average e.m.f.
Topics: Oscillations (58)
Subject: Physics (2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
18000+ students are using NEETLab to improve their score. What about you?
Solve Previous Year MCQs, Mock Tests, Topicwise Practice Tests, Identify Weak Topics, Formula Flash cards and much more is available in NEETLab Android App to improve your NEET score.
Share this page with your friends
Leave a Reply