| ⇦ |
| ⇨ |
If the ratio of amplitude of two superposed waves is 2:1, then the ratio of maximum intensity and minimum intensity is
Options
(a) (9:1)
(b) (1:9)
(c) (4:1)
(d) (1:4)
Correct Answer:
(9:1)
Explanation:
Let ɑ and b the amplitude of wave.
Given: ɑ / b = 2 / 1 (or) ɑ = 2b
I(max) / I(min) = (ɑ + b)² / (ɑ – b)² = 9 / 1
Related Questions: - A heavy stone hanging from a massless string of length 15 m is projected
- Two charges each equal to 2µ C are 0.5m apart. If both of them exist inside vacuum
- In the phenomenon of electric discharge through gases at low pressure,
- The potential differences across the resistance, capacitance and inductance
- A coil of 100 turns carries a current of 5 mA and creates a magnetic flux of 10⁻⁵ Wb.
Topics: Wave Optics
(101)
Subject: Physics
(2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
- A heavy stone hanging from a massless string of length 15 m is projected
- Two charges each equal to 2µ C are 0.5m apart. If both of them exist inside vacuum
- In the phenomenon of electric discharge through gases at low pressure,
- The potential differences across the resistance, capacitance and inductance
- A coil of 100 turns carries a current of 5 mA and creates a magnetic flux of 10⁻⁵ Wb.
Topics: Wave Optics (101)
Subject: Physics (2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
18000+ students are using NEETLab to improve their score. What about you?
Solve Previous Year MCQs, Mock Tests, Topicwise Practice Tests, Identify Weak Topics, Formula Flash cards and much more is available in NEETLab Android App to improve your NEET score.
Share this page with your friends

Leave a Reply