| ⇦ | 
| ⇨ |
If the ratio of amplitude of two superposed waves is 2:1, then the ratio of maximum intensity and minimum intensity is
Options
(a) (9:1)
(b) (1:9)
(c) (4:1)
(d) (1:4)
Correct Answer:
(9:1)
Explanation:
Let ɑ and b the amplitude of wave.
Given: ɑ / b = 2 / 1 (or) ɑ = 2b
I(max) / I(min) = (ɑ + b)² / (ɑ – b)² = 9 / 1
Related Questions: - Three capacitors each of capacitance C and of breakdown voltage V are joined in series
- Application of Bernoulli’s theorem can be seen in
- Two parallel metal plates having charges +Q and -Q face each other at a certain
- A particle with charge q is moving along a circle of radius R with unoform speed v.
- SI unit of magnetic dipole moment is
Topics: Wave Optics
(101)
Subject: Physics
(2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
- Three capacitors each of capacitance C and of breakdown voltage V are joined in series
- Application of Bernoulli’s theorem can be seen in
- Two parallel metal plates having charges +Q and -Q face each other at a certain
- A particle with charge q is moving along a circle of radius R with unoform speed v.
- SI unit of magnetic dipole moment is
Topics: Wave Optics (101)
Subject: Physics (2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
18000+ students are using NEETLab to improve their score. What about you?
Solve Previous Year MCQs, Mock Tests, Topicwise Practice Tests, Identify Weak Topics, Formula Flash cards and much more is available in NEETLab Android App to improve your NEET score.
Share this page with your friends
Leave a Reply