| ⇦ |
| ⇨ |
If the ratio of amplitude of two superposed waves is 2:1, then the ratio of maximum intensity and minimum intensity is
Options
(a) (9:1)
(b) (1:9)
(c) (4:1)
(d) (1:4)
Correct Answer:
(9:1)
Explanation:
Let ɑ and b the amplitude of wave.
Given: ɑ / b = 2 / 1 (or) ɑ = 2b
I(max) / I(min) = (ɑ + b)² / (ɑ – b)² = 9 / 1
Related Questions: - The approxiamate ratio of nuclear mass densities of ₇₉Au¹⁹⁷ and ₄₇ Ag¹⁰⁷ nuclei is
- The temperature of a metal block is increased from 27⁰C to 84⁰C. The rate of radiated energy
- A charge Q is enclosed by a Gaussian spherical surface of radius R
- If the length of a closed organ pipe is 1.5 m and velocity of sound is 330 m/s,
- Consider a compound slab consisting of two different materials having equal thickness
Topics: Wave Optics
(101)
Subject: Physics
(2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
- The approxiamate ratio of nuclear mass densities of ₇₉Au¹⁹⁷ and ₄₇ Ag¹⁰⁷ nuclei is
- The temperature of a metal block is increased from 27⁰C to 84⁰C. The rate of radiated energy
- A charge Q is enclosed by a Gaussian spherical surface of radius R
- If the length of a closed organ pipe is 1.5 m and velocity of sound is 330 m/s,
- Consider a compound slab consisting of two different materials having equal thickness
Topics: Wave Optics (101)
Subject: Physics (2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
18000+ students are using NEETLab to improve their score. What about you?
Solve Previous Year MCQs, Mock Tests, Topicwise Practice Tests, Identify Weak Topics, Formula Flash cards and much more is available in NEETLab Android App to improve your NEET score.
Share this page with your friends

Leave a Reply