| ⇦ | 
| ⇨ |
The potential energy of a simple harmonic oscillator when the particle is half way to its end point is (where E is the total energy)
Options
(a) E/8
(b) E/4
(c) E/2
(d) 2E/3
Correct Answer:
E/4
Explanation:
P.E. = (1/2) mω²y² ⇒ At y = a/2 ⇒ (1/2) (mω²a²/4)
Total energy (E) = P.E. at extreme position = (1/2) mω²a²
P.E. = (1/4).[(1/2) mω²a²] = E/4
Related Questions: - Nickel shows ferromagnetic property at room temperature. If the temperature is
- A step-down transformer has 50 turns on secondary and 1000 turns on primary winding.
- A circular road of radius 1000m has banking angle 45°.The maximum safe speed of a car
- Electric field at a point of distance r from a uniformly charged wire of infinite
- A certain metallic surface is illuminated with monochromatic light of wavelength
Topics: Oscillations
(58)
Subject: Physics
(2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
- Nickel shows ferromagnetic property at room temperature. If the temperature is
- A step-down transformer has 50 turns on secondary and 1000 turns on primary winding.
- A circular road of radius 1000m has banking angle 45°.The maximum safe speed of a car
- Electric field at a point of distance r from a uniformly charged wire of infinite
- A certain metallic surface is illuminated with monochromatic light of wavelength
Topics: Oscillations (58)
Subject: Physics (2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
18000+ students are using NEETLab to improve their score. What about you?
Solve Previous Year MCQs, Mock Tests, Topicwise Practice Tests, Identify Weak Topics, Formula Flash cards and much more is available in NEETLab Android App to improve your NEET score.
Share this page with your friends
Leave a Reply