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The potential energy of a simple harmonic oscillator when the particle is half way to its end point is (where E is the total energy)
Options
(a) E/8
(b) E/4
(c) E/2
(d) 2E/3
Correct Answer:
E/4
Explanation:
P.E. = (1/2) mω²y² ⇒ At y = a/2 ⇒ (1/2) (mω²a²/4)
Total energy (E) = P.E. at extreme position = (1/2) mω²a²
P.E. = (1/4).[(1/2) mω²a²] = E/4
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Topics: Oscillations
(58)
Subject: Physics
(2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
- A black body at 227⁰C radiates heat at the rate of 7cals/cm²s. At a temperature
- A moving coil galvanometer of resistance 100 Ω is converted to ammeter by a resistance
- A particle of mass 1.96×10⁻¹⁵ kg is kept in equilibrium between two horizontal metal
- The numebr 0 (zero) is required for
- In Young’s double slit experiment, the ratio of maximum and minimum intensities
Topics: Oscillations (58)
Subject: Physics (2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
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