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The potential energy of a simple harmonic oscillator when the particle is half way to its end point is (where E is the total energy)
Options
(a) E/8
(b) E/4
(c) E/2
(d) 2E/3
Correct Answer:
E/4
Explanation:
P.E. = (1/2) mω²y² ⇒ At y = a/2 ⇒ (1/2) (mω²a²/4)
Total energy (E) = P.E. at extreme position = (1/2) mω²a²
P.E. = (1/4).[(1/2) mω²a²] = E/4
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Topics: Oscillations
(58)
Subject: Physics
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Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
- When a wire of uniform cross-section a, length l and resistance R
- The angular velocity of a wheel increases from 100 rps to 300 rps in 10 seconds.
- Two parallel long wires carry currents i₁ and i₂ with i₁ > i₂ .
- A circular disc of radius R is removed from a bigger circular disc of radius 2R
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Subject: Physics (2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
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